0=sin(x)-π/6
.55 and 2.59 (+ or - 2π)
In Law of Sines what is the Ambiguous case
SSA
Find eq
see graphing 100
y=5sin(x)
y = x
1 = cos(theta) / sin(theta)
5=cos(π(x))+4
0 and 2 ( + or - 2)
See picture 1
Is B less than or greater than 50o
Less than because 3>7
Find the graph
y=-2cos(x-(pi/2))+6
see graphing 200
y = (3x - 12 ) ^ 2
sin(theta) / 72 cos(theta) - 144 / 9 cos^2(theta) = r
3/2=2cos(4(1+x))+3
-.395 and -.035 (+ or - π/2)
Use law of sines to solve for B
See Picture 2
22.69o
Find the eq:
see graphing 300
4sec(pi/2(x-4))-4
2 + y = -4x - 11 / 6
23 + 6 sin(theta) / 4 cos(theta) = r
1/2=3sec(π/2(x))+5
1.46 and 2.54 (+ or - 4)
Solve for b
see picture 3
b=3.0064
Find graph:
y=-tan(pi/4(x-5))+3
see graphing 400
r = 8 / 7 r cos(theta) - 4 r sin(theta)
7x - 4y = 8
5/3=π/6cot(3/2(π/4+x))+7/2
-.97 and -3.07 (+ or - 2π/3)
solve the triangle (round to nearest hundredth and DMS)
See picture 4
a=3.68
B=43o12'58.955"
C=106o31'57.634"
Find the polar eq, then graph
y=7x+4
See graphing 500
r = sqrt12 / 8 sec(theta)
x^2 + y^2 = x sqrt12 / 8