What is the slope of a line passing through the points (2, 4) and (4, 6)?
1
(x + 1) (x + 2)
x2 + 3x + 2
2 - x = 10
x = -8
x2 + 13x + 30
(x+3) (x+10)
What is the domain of the function f(x) = 2x – 4?
(-∞, ∞)
What the equation of a line with the slope of a 3 passing through the point (2, 4)?
y=3x-2
(x-6)(x+6)
x2 -36
x3 -125=0
x = 5
6x3- 4x2 – 16x
2x(3x2 -2x-8)
solve for x and y
y = –3x + 4
x + 4y = –6
x=2
y=-2
Line L passes through the points (4 , -5) and (3 , 7).
What is the equation of Line L in slope intercept form?
slope = -12
y=-12x +43
(2x2 + 1) (3x - 4)
6x3-4x2+3x - 4
-5x + 3 > 33
x = -6
y2 + 10y - 24
(y + 12)(y - 2)
simplify:
(-3a4 /5a6b-3)2
9b6/25a4
What is the slope of the line with an x-intercept at (3 , 0) and a y-intercept at (0 , -5)? Write an equation for the line in the slope intercept form.
slope = 5/3
y=5/3x-5
(m - 7) (m3 - 2m - 1)
m4 - 7m3 - 2m2 + 13m - 7
19 = 3|x - 2| + 4
Key to solving is you must set your equation equal to 19, -19
x = -3,7
4x2-16x+7
(2x-1)(2x-7)
(2 + 5i) (7 - 2i2)
18 + 45i
What is the slope of a line 3x+2y=4
slope= -3/2
y=(-3/2)x + 2
(x2 +5) (x2 -11x+6)
x4-11x3+11x2-55x+30
J-X= (J+X)/C
X=J(C-1)/(C+1)
9x4+45x2+14
(3x2+14)(3x2+1)
Use the Quadratic formula to solve this equation:
5x2 + 6x – 3 = 0
x= (-3/5) +- (2√6)/5