Find the inverse of the function:
f(x) = 2x3 + 3
cube root ( (x - 3) / 2)
Expand the logarithm:
log(ab)2
2 log(a) + 2 log(b)
What is the starting point for the function:
y = 4cosθ
(0,4)
2n2 - 2 + 3n
quadratic trinomial
Simplify the expression:
(6 + i) (-8 + 3i)
-51 + 10i
Rewrite in logarithmic form:
xy = 101
logx101 = y
Condense the logarithm:
log3u - 5 log3v
log3(u/v5)
What is the midline for the function:
y = 3sinθ-2
y=-2
Find the zeros of the polynomial:
f(x) = 2x4 + 2x3 - 12x2
x = {2, 0 (mult, 2), -3}
Find the aboslute value of the complex number:
|2 - 4i|
2 sqrt(5)
Evaluate the logarithm:
log6(1/216)
-3
Condence the logarithm:
20 log6x + 5 log6y
log6(x20y5)
What is the period of the function:
y = tan3θ
π/3
Divide:
(2x2 + 5x - 42) / (x + 6)
2x - 7
Sketch a graph with one real root and two complex roots.
*on graph*
Rewrite in exponential form:
log550 = k
5k = 50
Expand the logarithm:
log4(xy/z)
log4x + log4y - log4z
Describe the phase shift AND vertical shift of the function:
y = 4 sin (θ - π/4) - 1
Phase shift: right π/4
Vartical shift: down 1
Divide:
(6a2 + 24a - 36) / (a + 5)
6a - 6 - (6/(a+5))
Find the equation of the function that has the roots:
(2 + 5i) and (2 - 5i)
y = x2 - 4x + 29
State if the following functions are inverses:
f(x) = (2/(n+1)) + 1
g(x) = (1/(n+1)) + 2
no
Condense the logarithm:
2(log5a + log5b) - log5c
log5((a2b2)/c)
What is the starting/center point for the function:
y = 3 cos (θ + π) + 2
(-π, 5)
Divide:
(k3 - 17k + 8) / (k - 4)
k2 + 4k - 1 + (4/(k-4))
Solve using the quadratic formula:
0 = x2 - 6x + 12
3 +/- i sqrt(3)