Where is the end point on the function?
f(x)=sqrt(x+2)
( -2 , 0 )
Sketch the function
f(x)=root(3)(x)
graph
Find the average rate of change from point A to point B.
Point A: (0, 3)
Point B: (4, 5)
(5-3)/(4-0)=2/4=0.5
Where is the end point on the function?
f(x)=-sqrt(x-1)
( 1 , 0 )
Where is the point of symmetry on the function?
f(x)=root(3)(x+2)-1
( -2, -1 )
Find the average rate of change from point A to point B.
Point A: (-1, 5)
Point B: (2, 8)
(8-5)/(2--1)=3/3=1
What is the domain of the function?
f(x)=-sqrt(x+3)
[-3, oo)
What is the domain of the function?
f(x)=root(3)(x+2)-1
(-oo, oo)
Find f(2)
f(x)=sqrtx+2
f(2)=sqrt2+2=3.41
What is the range of the function?
f(x)=-sqrt(x+3)
(-oo, 0]
What is the decreasing interval for the function?
f(x)=root(3)(x+2)-1
none
Find the average rate of change on the interval
[ -2 , 1]
f(x)=root(3)(x+3)-1
0.2
What is the decreasing interval of the function?
f(x)=-sqrt(x-2)
(2, oo)
What is the increasing interval for the function?
f(x)=root(3)(x+2)-1
(-oo,oo)
Find the average rate of change on the interval
[ -2 , 1]
f(x)=sqrt(x+5)
0.24