The line going through (-4.8, 0) with a slope of -14
y = -14x - 4.8
the roots of f(x) = (x+4)(x-9)
x = -4, 9
sqrt(196x^2)
14x
Function or Not? 
Not a function!
the range of
f(x) = 4x^5-9x^3+2x^2-9
all real numbers
the line going through the point (-4, 19) with a slope of 5
y = 5x + 39
the roots of f(x)=x^2+2x-63
x = -9, 7
root(3)(135x^4)
3xroot(3)(5x)
f(x)=54/x+11.5
Find f(17)
f(17) = 14.5
the domain of f(x) = x/(x-3)
x !=3
(-infty,3)cup (3,infty)
-infty < x < 3 and 3 < x <infty
the line going through (-7, 9) that is perpendicular to -7
y=1/7x+10
the roots of
f(x)=5x^2-30x-80
x = -2, 8
3sqrt10+9sqrt360
57sqrt10
g(x) = 9x^2-14
Find g(x^2)
g(x^2)=9x^4-14
the domain of h(x)=sqrt(3x-36)
xgeq12 OR [12,infty)
the horizontal line going through the points (16.7, 4) and (-112, 4)
y = 4
the roots of f(x)=3x^2+2x-8
x = -2, 4/3
2root(3)(448m^6n^10
8m^2n^3root(3)(7n)
f(x)=3x^2-15
Find f(x+4)
3x^2+24x+33
the domain of f(x)=1/3cos(x-1)
all real numbers
the line going through the points (5, 17) and (11, 12)
y=-5/6x+127/6
y=x^2+10x+12 in vertex form
y=(x+5)^2-19
isqrt(-98x^3)+6(i+2)-6i-5
-7xsqrt(2x)+12
f(x)=12x-5 and g(x)=78/x
Find f(g(3))
307
the domain of f(x) = (sqrt(1-x))/(x^2-16)
(-infty,-4) cup(-4,1]