At x=3, f(x) is increasing. What do you know about the derivative at x=3?
It is positive.
If
f(x)=2x^3-x^2+5x+10
13
Find the derivative of
g(x)=e^(x)-ln(x^2)+x^3
g'(x)=e^(x)-(2/x)+3x^2
What is the equation of the line tangent to
y=-3x^2+1
at the point x=-1 ?
y+2=6(x+1)
Identify the points where the function is nondifferentiable. 
x = -2, -1, 0, 2
lim_(h->0)(4(x+h)^3-4x^3)/(h)=
12x^2
Find the derivative of
g(x)=sqrt(x)-3/x^4
g'(x)=1/(2sqrt(x))+12/x^5
Find the second derivative of
h(x)=e^(mx)+1/x
h''(x)=m^2 e^(mx)+2/x^3
Use the tangent line at x = 2 to approximate the value of f(2.2) given that
f(x)=2x^3-x
y=18.6
Identify all points where the function is non-differentiable. 
x = -1, 1, 2, 2.5
lim_(h->0)(2(-1+h)^4-2)/(h)=
-8
Find the derivative of
f(x)=4^(5x)+sqrt(x-2)
f'(x)=5(4^(5x))ln(4)+1/(2sqrt(x-2))
Find the second derivative of
h(x)=5ln(sqrt(x))
h''(x)=-5/(2x^2)
Find the slope of the line normal to
f(x)=3e^(4x)-sqrt(x+1)
at x = 0.
-2/23

(D)
Given that
lim_(h->0)(f(-2+h)-f(-2))/(h)=3
Which of the following statements must be true? Select all that apply.
I. f(x) is positive
II. f(x) is increasing
III. The slope of the line tangent to f(x) is increasing
II only
What is the derivative of
g(x)=6x^2-sqrt(x-3)+ln(3x^5+1)
where x = 3
Does not exist!
What is the slope of the line tangent to
h(x)=e^(x-3)/4+5sqrt(x)-ln(x^2)
h'(x)=e^(x-3)/4+5/(2sqrt(x))-2/x
Find an equation of the line tangent to f(x) at x = 2:
f(x)=e^(3x)-12/x^2
y-(e^8-3)=(3e^8+3)(x-2)
Find the values of a and b that make the function differentiable:
f(x)={(asqrt(x),x>1),(bx^2+9, xleq1):}
a = 12, b = 3