f(x)=cos2(x)
What is the outer function? What is the inner function?
Outer: ( )2
Inner: cosx
Find the slope of the line tangent to f(x)=−3cos(3x) at x=pi/3
f′(x)=9sin(3x)
f'(pi/3)=0
Find equation for the slope of the line tangent to y=2cot2(x)
y'=−4cot(x)csc2(x)
Given the function f(x)=(8−7x3)(−5x3−7−3x2), find f′(x) in any form.
f'(x)=(−21x2)(−5x3−7−3x2)+(−15x2−6x)(8−7x3)
y= (1+x2)/(2x2+3)
y'=(2x)/(2x2+3)2
Given the function y=4x3−4xcosx, find y' in any form.
y'=12x2−4cosx+4xsinx
Given the function f(x)=(3x3−4x)sinx, find f′(x) in any form.
f′(x)=(9x2−4)(sinx)+(cosx)(3x3−4x)
y=sinx/(1-2x)
y'=((1-2x)cosx+2sinx)/(1-2x)2
For the function f(x)=x2+8, find the equation of the tangent line at x=−5.
y−33=−10(x+5)
Find the derivative of f(x)=2cosx-5cotx
f'(x)=-2sinx+5csc2x
y=radical(x)cosx, y'=
No negative exponents, no rational exponents.
y'=(1/2x−1/2)(cosx)−(sinx)(x1/2)
y=tanx/secx
Write in SIMPLEST form. Use those trig identities!!
y'=(sec3x-secxtan2x)/sec2x
y'=cosx
Given f(x)=3cos(x), write the equation of the line tangent toy=f(x) when x=π/6.
y=-(3/2)(x-pi/6)+(3rad(3)/2)