Solve for the Derivative:
y = x3 - x2 + x - 1
3x2 - 2x + 1
Evaluate:
∫ [3x2 + 5] dx
x3 + 5x + C
Find the Limit:
limx→5 x2 + 1
26
If a particle's velocity is negative with a positive acceleration, is the particles speed increasing or decreasing?
decreasing
Solve for the Derivative:
y = ln(x)
1/x
Evaluate:
∫ [4cos(3x)] dx
4/3 sin(3x) + c
Find the limit:
limx→-3 (x2 + x - 6)/(x + 3)
-5
What are the critical values?
f(x) = x2 + 4x + 5
-2
Solve for the Derivative:
y = (ex)(sinx)
(ex)(sinx) + (ex)(cosx)
Evaluate:
∫ [(du)/(a2 + u2]
(1/a)arctan(u/a) + c
Find the Limit:
limx→1 (((x + 1)1/2) - 1)/(x)
1/2
Find the linear approximation of f(x) = 2x2 + 3x + 4 at x = -2. Use the linearization to approximate f(-1.9)
5.5
Solve for the Derivative:
y = -2(1 + x)4
-8(1 + x)2
Evaluate on the interval [0,4]:
∫ [3x4 - 3x2] dx
2752/5
Find the Limit (L'Hopital's Rule):
limx→2 (x3 + 7x2 + 10x)/(x2 + x -6)
-6/5
Write an equation to find the area between the curves.
Curve 1: y =1
Curve 2: y =cos2x
A = ∫ [(1 - cos2x)] dx
(integral from 0 to π)
Solve for the Derivative:
y = (2x2 + 5x + 1)3
3(2x2 + 5x + 1)2(4x + 5)
Evaluate (u-sub):
∫ [x(x+3)1/2] dx
(2u5/2/5) - (2u3/2) + c
Find the Limit:
limx→-2 (x3 + 8)/(x2 - 4)
-3
We have 45m2 of material to build a box with a square base and no top. Determine the dimensions that maximize the volume.
(Calculator)
length = width = 3.873
height = 1.9365