Slope of a Tangent Line
Limit Evaluation
Absolute Max/Min Values
Definite Integral
Average Value
100

Find the derivative of the function

f(x) = 3x- 6x + 788

f'(x) = 6x-6

100
Find the limit at x = 0 for the function f(x) = 3x2 + 2
The limit = 2
100

Find the absolute maximum of f(x) from the interval [0, 2].

f(x) = x2

Absolute Max: 4 at x = 2


100

Evaluate the Integral

0(4x)dx

18

100

Find the average value of f(x) = 6x on the interval [0, 4].


12

200

Find the slope of the line tangent to the function g(x) = 2x- 4x2 + 6x at x = 3

g'(3) = 36

200

Find the following limit.

limx→∞  (x2)/(3x)

The limit =

200

Find all absolute maximums for the function g(x) = 3sin(x) + 2 from the interval [0, 2π]


5 at x = π/2

200

Find the integral for the equation of g(x) using the bounds [0, 2]

g(x) = (3x2 - 2x + 1)

6

200

Evaluate the average value of g(x) on the interval [0, 3].

g(x) = 3x2 - 2x

6

300

Find h'(5)

h(x) = x3ex + 2x

h'(5) = 200e5 + 2

          or

h'(5) = 29684.632

300
Find the following limit.

limx→3  (x2 - 9)/(x - 3)

The limit = 6

300

Find the absolute minimum of h(x) from the interval [-1, 3].

h(x) = x2 - 4x + 5

1 at x = 2

300

Find the integral of h(x) using the bounds [π, 2π]

h(x) = 3cos(x)

0

300

Evaluate the average value of h(x) on the interval [2, 4].

h(x) = x3 - 6x + 1

13

400

Find j''(2)

j(x) = x4 - 4x2 + ln(x)

j''(2) = 39.75

        or

j''(2) = 159/4

400

Find the limit PLEASE.

limx→∞   (5x2 - 3x + 26)/(2x2 - 9)

The limit = 5/2

400

Find the minimum value(s) for the function j(x) on the interval [0, 4].

j(x) = (x2 + 9)/x

6 at x=3

400

Evaluate the following integral.

0π/2 [sin(2x)]dx

1


400

Find the average value of j(x) = 5x2 + 7x - 3 on the interval [-2, 2].

11/3

500

Find the equation of the line tangent to the function k(x) = cos(x2+5) + sin(x) at x = 0

y = x + cos(5)

       or

y = x + 0.284

500

Evaluate the limit.

limx→-4  (x2 + 2x - 8)/(x+4)

The limit = -6

500

Find the absolute maximum value(s) for the function on the interval [-1, 2].

k(x) = 2x3 - 3x2 - 12x + 1

8 at x = -1

500

Solve the following definite integral equation.

24 (2x3+3x2+4x+5)dx

210

500

Find the average value of k(x) on the interval [0, 5]

k(x) = x2 + ex

(122/15) + (e5/5)

            or

        37.816

M
e
n
u