Applications of Derivatives
Antiderivatives
Definite Integrals
Area Under a Curve
U Substitutions
100

It is the derivative of the function at the given value

y = x2 + 4x at x = −5  

y = x2 + 4x at x = −5 

 dx/dy x=-5   =-6

       What is -6

100

It is the Anti Derivative of:

3x2

What is x3 + c

100

It is the evaluation of the definite integral.

y = − x2/2 + x − 1/2 ; [−2, 1]

What is -1/2

100

It is the area under the curve over the given interval.

y=4/x2 ; [-2,-1]

I-1-2 4/x2 dx

What is 2

100

It is the U value of the substitution.

I20 2x[x2+4]2dx  

What is u=x2+4

200

It is the slope of the function at the given value.

y = x2 + 6x + 7 at x = −2

y = x2 + 6x + 7

y'=2x+6

y'=2(-2) + 6

What is 2

200

It is the Anti Derivative of: 

sec2(x)

What is tan(x) + c

200

It is the evaluation of the definite integral.

y = x2/2 − 2x − 1; [−1, 1]

What is 0

200

It is the area under the curve over the given interval.

y=sec2(x) ; [-pi , -3pi/4]


I-pi-3pi/4 sec2(x) dx

What is 1

200

It is the U value of the substitution.

I0-1 18x2(3x2+3)2 dx 

What is u=3x2+3


300

It is the equation of the line tangent to the function at the given point. Your answer should be in slope-intercept form

y = x3 − 3x2 + 2 at (3, 2)

y = x3 − 3x2 + 2

y'=3x2- 6x

y'=3(3)2-6(3) =9   y=9x+b  

(2)=9(3)+b 

2=27+b   b=-25     What is y=9x-25

300

It is the Anti Derivative of: 

1/(1-x2)1/2

What is sin-1(x) + c

300

It is the evaluation of the definite integral.

y = x3 + 3x− 2; [−2, 0]

What is { (−3 + (3)1/2)/3 , (−3 − (3)1/2)/3 } 

300

It is the area under the curve over the given interval.

y=(x)1/2

I54 (x)1/2 dx

What is 2(5(5)1/2-8) / 3 = 2.12

300

It is the derivative of the U value of the substitution.

I20 2x[x2+4]2dx  

U=x2+4

du=2x dx

What is du= 2x dx

400

It is the values of c that satisfy the Mean Value Theorem

y = −x2 + 8x − 17 ; [3, 6] 

y = −x2 + 8x − 17

y'= -2x + 8

-1 = -2c + 8

What is 9/2

400

It is the Anti Derivative of: 

sec(x)

What is ln|sec(x)+tan(x)| + c

400

It is the evaluation of the definite integral.

y = −x3 + 4x2 − 3; [0, 4]

What is 8/3

400

It is the area under the curve over the given interval.

y=-cos(x) ; [3pi/4 , pi]

Ipi3pi/4 -cos(x) dx

(2)1/2/2

What is 0.707

400

It is the integral of this equation.

I116x/(4x2+4)2 dx ; u=4x2+4

What is 1/4=.25

500

It is the slope of the function at the given value.

y = −ln (−x + 2) at x = −3

y = −ln (−x + 2)

y'= 1/-x+2

y'= 1/-(-3)+2

What is 1/5

500

It is the Anti Derivative of: 

1/(a2+x2)

What is 1/a tan-1(x/a) + c

500

It is the evaluation of the definite integral.

y = −(−5x + 25)1/2 ; [3, 5]

What is 9/2

500

It is the area under the curve over the given interval.

y=6x2+6x ; [-.5 , .5]

What is 0

500

It is the integral of this expression.

I (3x+2)5 dx

(3x+2)6/18 +c

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