Extreme Values
Mean Value Theorem
Modeling and Optimization
Curve Sketching
Related Rates
100

True or False: The absolute maximum of the function f(x) = 4x - x2 + 6 on the interval [0,4] is 10.

True

100

Suppose f(x) is continuous on [2,5] and -3 < f '(x) < 3 for all x. True or False: If f(2) = 11, then f(5) could be 22.

FALSE: The maximum possible value of f(5) is 11+(5-2)(3) = 11+9 = 20. The minimum possible value of f(5) is 11 + (5-2)(-3) = 11-9 = 2. 22 is not in this range.

100
List the steps of optimization.
1) Draw and label picture 2) Create a variable (s) that represents the value to be found 3) Write a function in terms of the principal variables (substitution) 4) Find domain 5) Set f'(x) = 0 and perform first derivative test 6) Check answer graphically, don't forget units
100
The function increasing. f(x)=x^4-3x^3+x^2-1
What is (0, 0.25), (2, inf)?
100
True or False: If the height of a right circular cone is increasing at a constant rate, then the volume of the cone is also increasing at a constant rate.
False. The volume of a cone depends on its radius! (For extra happiness, prove how!)
200
State the Extreme Value Theorem.
If a function f(x) is continuous on the interval [a,b], then f(x) has both a maximum value and a minimum value on the interval [a,b].
200
When does a given function satisfy the conditions of the Mean Value Theorem?
When the function is continuous over [a,b] and differentiable over (a,b).
200
Find two positive numbers whose sum is 47 and whose product is as large as possible.
47/2 and 47/2 This is true for any question like this!
200
The function decreasing. f(x)=x^4-3x^3+x^2-1
What is (-inf, 0), (0.25, 2)?
200
List the steps of solving a Related Rates problem.
1) Draw and label a diagram 2) Write down what you're trying to find and what you know 3) Set up an equation that relates the variables 4) Differentiate both sides with respect to t 5) Solve for the specific variable 6) Write down the answer with units
300

How many critical points does the function 

f'(x) = (x-2)5(x+3)4 have?

2

300

Find a value of c such that the conclusion of the mean value theorem is satisfied for f(x) = -2x3 + 6x - 2 on the interval [-2 , 2].

f(-2) = -2(-2)3 + 6(-2) - 2 = 2

f(2) = -2(2)3 + 6(2) - 2 = - 6

[f(b) - f(a)] / (b - a) = [ -6 - 2 ] / (2 - -2) = -2

f '(x) = -6x2 + 6

-6c2 + 6 = -2

c2 = 4/3

c = plus or minus 2/sqrt(3)

300
A girl is building a house without a roof. She has a sheet of cardboard that is 10 ft by 10 ft. Where and how much does she have to cut to make a roofless house with the largest possible volume?
She has to cut four 0.1 ft by 0.1 ft squares out of the four corners of the box.
300
The function is concave up. f(x)=x^4-3x^3+x^2-1
What is (-inf, 0.121), (1.379, inf)?
300
Some bored kids are trying to increase the size of a 6-inch deep cardboard tube with a homemade machine (these are cool kids) that increases the tube's radius 1/1000th of an inch every three minutes. How rapidly is the tube's volume increasing when the diameter is 3.8 inches?
V= πr^2(h) dV/dt = 2πr(dr/dt)(6) = 2π(1.9)(1/3000)(6) = .024 cubic inches / min
400

Find the critical points of the function 

f(x) = x / (x2 + 1). 

State whether each is a maximum, minimum or neither.

Max: (1,1/2) Min: (-1,-1/2)

400

Let f(x) = c(x2) + dx + e where c does not equal 0. Show how many points of inflection the graph has. 

None

400
Two guys are hanging from bungee cords. Guy 1's position is represented by the equation P = 2sinT. Guy 2's position is represented by the equation P = sin2t. P is in meters and T is in seconds. a) At what times in the interval T>0 do the guys pass each other? b) When in the interval [T is between 0 and 2π, inclusive] is the vertical distance between the guys the greatest? What is the distance? We'll give you up to 2 hints for 100 points each.
HINT 1: sin2T = 2sinTcosT



HINT 2: cos2T = 2cos^2(T) - 1



ANSWERS: a) Whenever T is an integer multiple of π seconds. b) The greatest distance is (3√3)/2 meters when T = 2π/3 and 4π/3 seconds.
400
The function is concave down. f(x)=x^4-3x^3+x^2-1
What is (0.121, 1.379)?
400
Given the equation PV=nRT with P, V, and n as constants, find dT/dt.
dT/dt = (PV/n)(dR/dt)
500

The volume of an orange crate can be represented by the function: V(x) = x(10 - 2x)(16 - 2x) over the domain 0 < x < 5 Find the maximum volume of the crate.

Max: 144 at x = 2 The largest possible volume of the crate is 144 cubic units, which occurs when x = 2.

500
So there's a train, in Europe. It's going slowly, speeding up, and then slowing down again. Kind of like f(x) = (x^3)[(sin(x))^2] + 15(x^2). x is time in hours and f(x), or y, is distance in miles. Graph it! [Give us 200 points if you do it with your calculator.] Then look at t between 1 and 6, inclusive. Label points! Now, look at velocity with units. Draw a picture, if you'd like. What does this all mean? What does it have to do with the mean value theorem?
Unsimplified, v= [(3x^2)((sin^2)x)+2sinxcosx(x^3)] + 30x So, in that window the train just keeps speeding up. The mean value theorem tells us that at some point on that interval, there's some point in between where it hits a certain point, which is the "average." For extra happiness, find it.
500
The reaction of a body to a dose of medicine can be represented by the equation R = M^2 ((C/2)-(M/3)) where: C is a positive constant (pretend it's 6) M is the amount of medicine absorbed in the blood If the reaction is a change in pressure, R is measured in mmHg, and if it's a change in temperature, R is measured in degrees, ad nauseum. Find dR/dM. Then find the amount of medicine to which the body is most sensitive. Hint for 100 points.
HINT: Find the value of M that maximizes dR/dM.




ANSWER: M = 6/2 = 3
500
The function's concavity changes. f(x)=x^4-3x^3+x^2-1
What is x= 0.121 and x=1.379?
500
Some really cool guy came up with an equation for how much blood the heart pumps. It can be calculated with the formula y=Q/D where: Q=mL CO2 exhaled in a minute (= 233 mL/min) D= difference beween CO2 concentration in blood going to lungs and blood going from lungs (= 97-56 = 41 mL/L) D is decreasing by 2 units per minute, and Q remains unchanged. What happens to cardiac output? (For 100 points, you can have a hint.)
dy/dt = [D(dQ/dt) - Q(dD/dt)] / D^2 dy/dt = 0 - 233(2) / 41^2 = .277 L/min
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