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A 0.0025M solution of HI (aq) has [H3O+] = 0.0025M. Calculate the [I-], [OH-], and the pH of the solution.
pH is determined from [H30+], pH = -log [H3O=] = -log (.0025) = 2.60
We know that HI is a strong acid and this completely dissociated into H3O+ and I-.
The consequence is that [I-] = [H3O+] = 0.0025M. [OH-] is most readily computed from pH: pOH=14-pH= 14-2.60= 11.40 -->
[OH-] = 10^(-pOH) =4.0E-12