Variable substitution
5x
x=3
15
b3(bx)=b7
4
x5x7=x35
Multiplied exponents
x12
x4x3x5
x12
(x4/2y-3)0
1
3+4a
a=-5
-17
(b5)x=b40
8
(24)(34)= 64
Multiplied bases and kept exponents
1,296
(35)8
340
-8(xy3)0
-8
xy-y
x=3, y=-4
-8
b3/bx=b9
-6
43x42=46
Used the multiplication law on addition
80
24+32
25
(1/3)2
1/9
7y3+2y
y=-2
-60
62(6-x)=366
-4
(2b2)(5b6)=7b8
They should have multiplied the 2 and 5.
10b8
x6y9/x5y4
xy5
(7x3y5)2
49x6y10