Rewrite Exp. or Log. Functions
Compound Interest
Growth or Decay
(and Why?)
Transformations And Functions
Solve it!
(log solutions as log or ln only)
Properties of Logarithms!
100

log1/2(256)=-8

(1/2)-8=256

100

You receive $5000 to invest in a bank account paying 4.5% interest compounded annually. If you leave the money in there for 15 years, how much will you have?

$9676.41

100

y=3(2)x

Growth, b>1

100

Write the Transformations

OG: y=3(2)x

NEW: y= -(3/4)(2)x-4 + 1

Reflection over the x-axis, vertical shrink by 1/4, vertical translation 1 up, horizontal translation 4 to the right

100

Solve 2x = 3

x=log23

100

Condense: log4 + logx - logz

log(4x/z)

200

10b=5

Log5=b

200

You receive $200 to invest in a bank account paying 12.1% interest compounded monthly. If you leave the money in there for 5 years, how much will you have?

$365.14

200

y=0.5(4)x

Growth, b>1

200

Write the Transformations

OG: y= log(x)+2

NEW: y= log(-2x) +4

Reflection over the y-axis, horizontal shrink by 1/2, vertical translation up 2 units

200

2x=4x-1

x=2

200

Expand: log9(2x2/y8)

log92 + 2log9x - 8log9y

300

Logwm=a

wa=m

300

If you invest $50 in a bank account paying 12% interest compounded quarterly, how long does it take if you wish to have $200?

t = 11.72 years

300

y=6(1/2)x

Decay, b<1

300

Write the function with the given transformations: 

OG: y=2x

Translate 4 units up, 3 units to the right, vertical stretch by 9

y= 9(2)x-3+4

300

log(x2+1)-log2=log13

x= 5, -5

300

Condense:

2lny + ln(x3/2) - lnz

ln(y2x3/2z)

400

e-3=1/20

ln(1/20)=-3

400

If you invest $322 in a bank account paying 2.2% interest compounded daily, how long does it take if you wish to have $400?

t= 9.86 years

400

y=3(1)x

Neither b=1

400

Write the function with the given transformations: 

OG: y=log5(x)

Translate 5 units to the left, Translate 3 units down, Vertical shrink by 1/3, Reflection over the x-axis

y= -(1/3)log5(x+5) - 3

400

log3812

8

400

Expand: log166(11*103/7z5)

log16611 + 3log16610 - log1667 - 5log166z

OR  log16611 + 3log16610 -(log1667 + 5log166z)

500

ln(x2-15x+56)=-17

e17=x2-15x+56

500

How much will you have at the end of 5 years if you leave $610 in an account with 8.4% interest compounded continuously?

$928.40

500

y=3(e)-x

Decay, x is negative

500

Write an exponential function that goes through the points (1, 15) (2, 45). 

y= 5(3)x

500

log2(x-1)+log2x=1

x=2

500

Condense: log2x + log5y - 2log2z + log5k

log2(x/z2) + log5(ky)

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