Means
Proportions
Choose the Test
Chi Squared
Calculations
100

When the population standard deviation is unknown, you should use this table.

T-table

100

If we want to see if there is a difference between the proportion of seniors who eat in the dining hall and the proportion of freshmen who eat in the dining hall, we should run this test.

2 proportion z test

100

Is political affiliation related to the month that the person was born in?  3000 voters were studied.

Chi-Square Test for Independence

100

This is the type of test we should run when we are looking at the distribution of categorical variables

Chi square GOF

100

Solve for x


40x + 30 = 20 - 10x

x = -0.20 

200

If we are going to compare the average weight of a sample of 100 bags of m&ms to the advertised average (12.0 oz), we should run this type of test. 

What is a t test

200

We want to see if there is a difference between the proportion of seniors who eat in the dining hall and the proportion of freshmen who eat in the dining hall. What is our null hypothesis (use plain english)?

There is no difference between the proportion of seniors and the proportion of freshmen who eat in the dining hall.

200

Are male swimmers faster than female swimmers? 40 men and 30 women were selected at random to swim in a 100-meter race.

Hyp. Test for the Difference Between 2 Means

200

What is our degrees of freedom is we have 5 columns and 3 rows in our table (chi square test for independence)?

8

200

Calculate the standard deviation of p hat if:

p = 0.34

n = 400

.0237

300

You are curious about the average number of hours that Asheville School students sleep each night. What inference method should you use?

What is a t interval

300

We want to see if there is a difference between the proportion of seniors who eat in the dining hall and the proportion of freshmen who eat in the dining hall, we run a test, and calculate a p value of .08. What can we conclude (in context).

We cannot reject the null hypothesis, because .08 > .05. There is not sufficient evidence to conclude that there is a difference between the proportion of freshman and the proportion of seniors who eat in the dining hall. 

300

You want to estimate the average number of texts that college students send each day.  You survey 150 college students.

Confidence interval for mean (t interval)

300

How do you calculate expected counts for a chi square test for independence?

Row total times column total divided by total total. 

300

What is the margin of error for the confidence interval (0.55, 0.72)

.085

400
We want to see the effect that a test prep program has on academic performance. We look at scores on a standardized test for 25 students before they take the program, and then measure those same students' performance again after the program. What type of test should we run?
t test for paired data
400

We want to see if there is a difference between the proportion of seniors who eat in the dining hall and the proportion of all students who eat in the dining hall. It is known that 80% of all students eat dinner in the dining hall. We sample 55 seniors, and find that 38 eat in the dining hall. What would a type 1 error be in context of this question?

We conclude that there is a difference between the proportion of seniors who eat in the dining hall and the proportion of all students who eat in the dining hall, when in fact there is no difference. 

400

Typically, your shop has 140 customers per day.  Over the last thirty days you have a special advertisement in the Daily Tribune.  You chart your daily number of customers.  Is this ad effective?

Hypothesis Test for a Population Mean (t test)

400

If we are running a chi square test for association to see if there is a difference between men and women with regards to their favorability rating for a new movie, what should our null hypothesis be?

There is no association between gender and favorability rating for the movie in question. 

400

Consider the weights of 18 month old boys in the U.S. According to published growth charts, the average weight is approximately 11.8 kg with standard deviation of 1.28 kg. Calculate the percentage of 18 month old boys in the U.S. who weigh between 10.5 kg and 14.4 kg.

0.9788 - 0.1539

= 0.8249

500

Pepsi claims that bubly has 12.0 oz in each can with a standard deviation of 0.1 oz. You take a random sample of 65 bubly cans, and measure the amount of water in each can. You then take the average of the cans in your sample. You find that the average of the cans in your sample is 11.95 oz. Is Pepsi underfilling their cans? What can you conclude (use p value in order to get credit)?

Reject null hypothesis, p = 2.777 x10 ^ -5

500

We want to see if there is a difference between the proportion of seniors who eat in the dining hall and the proportion of all students who eat in the dining hall. It is known that 80% of all students eat dinner in the dining hall. We sample 55 seniors, and find that 38 eat in the dining hall. Calculate the p value and draw a conclusion. 

p = .043

We can conclude that there is a difference between the proportion of seniors who eat in the dining hall and the proportion of all students who eat in the dining hall. 

500

The US Census bureau recently came out with the percents of Americans who are working in Service industry, Manufacturing, Unemployed and Other.  A researcher wants to find out if these percents are different in South Lake Tahoe.  100 people were surveyed.

Chi Square GOF

500

A professor thinks that 60% of his students will purchase his book, 25% will print it from the web, and 15% will read it online. At the end of the semester, he asks his class to complete a survey to indicate what format of the book they used. Of the 126 respondents, he finds that 71 bought the book, 30 printed from the web, and 25 read it online. Run a chi squared GOF test and calculate the p-value.

0.313

500

The probability of a type 1 error is .05, and the probability of a type 2 error is .10. The probability of a type 1 error then goes up to .10, and the probability of a type 2 error goes down to .05

Calculate the "power" in this new scenario.

0.95 (1-.05)

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