y = 5x
y'= 5
y=(X+1)2
y'=2(x+1)
y= (x3) / (x-5)
y'= (2x3–15x2) / (x-5)2
y=(2x2)(3x)
y'=18x2
Si el problema tiene COS que usas ???
- SIN
y = x2/3
y'= 2 / 3x1/3
y=(2x2 +3)3
y'=12x(2x+3)2
y=(x+1)/(x-1)
y'=-(2)/(x-1)2
y=(3x3)(3x3-2)
y'=54x5-18x6
Si el problema tiene TAN que usas ?
SEC2
y = 3 / x3
y'= -9 / x4
y=(2x5+5)1/4
y'=(5/2)x4(2x5+5)-3/4
y=(10)/(x2+3x-9)
y'=(-20x+30)/(x2+3x-9)2
y=(-5x5-3)(-3x3+4)
y'=120x7-100x4+21x2
y = cos x2
y' = -2x sin x2
y = (-1/2)x4 + 3x5/3 + 2x
y'= -2x3 + 5x2/3 + 2
y=(-5x2+2)1/2
y'=5x(5x2+2)-3/2
y=(x2+5)/(x-4)
y'=(x2-8x-5)/(x-4)2
y=(4x5+x3+5)(x5+2)
y'=40x9+8x7+130x4+6x2
y = sin 3x3
y'= 9x2 cos 3x3
y = (2/3)x4 + 5x -x-3
y'= (8x3) / (3 + 5 + 3/x4)
y=(4x2+3)-2
y'= -16x(4x2+3)-3
y=(5x5-x4)/(30x-12x2)
y'=-(180x6-624x5+90x4)/(30x-12x2)2
y=(X5/3-3)(-4x5+5x4+4)
y'=(-80/3)x17/3+(85/3)x14/3+60x4-60x3 +(20/3)x
y = tan 1/x4
y' = -4x-5 sec2 1/x4