What is a Bronsted-Lowery acid?
H+ donor
What is a Bronsted-Lowery base?
H+ accpetor
What is the Ka value if [H3O+]=4.8x10-3M, [HA]=0.0026M and [A-]=4.8x10-3M?
Ka=[H3O+][A-]/[HA]
=(4.8x10-3M)(4.8x10-3M)/(0.0026M)
=8.8x10-3
True or False: Strong acids partially ionize in water.
FALSE: strong acids completely ionize in water.
True or False: The stronger the acid, the weaker its conjugate base.
TRUE: The stronger the acid, the weaker its conjugate base.
What is the formula for Ka in terms of [A-],[HA] and [H3O+]?
Ka=[H3O+][A-]/[HA]
What is the formula for Kb in terms of [OH-][BH+] and[B]?
Kb=[BH+][OH−]/[B]
What is the Ka value if [H3O+]=6.2x10-3M, [A-]=1.5x10-3M and [HA]=0.0079M?
Ka=[H3O+][A-]/[HA]
=(6.2x10-3M)(1.5x10-3)/(0.0079M)
=1.17x10-3
Which of the three acids is the most extensively ionized in a 0.10 M solution of the acid?
A. Ka= 4.5x10-6
B. Ka=8.2x10-5
C. Ka=6.7x10-5
B. Ka=8.2x10-5
Which acid is stronger? Acid A with Ka=7.9x10-6 or Acid B with Ka=6.1x10-6.
Acid A
Because 7.9x10-6>6.1x10-6 & the bigger the Ka value, the stronger the acid.
Is an acid with a very small Ka value a strong acid or a weak acid?
Weak acid
Which describes a chemical that would be basic?
A. [H3O+]>1.0x10-7M
B. [H3O+]=1.0x10-7M
C. [H3O+]<1.0x10-7M
C. [H3O+]<1.0x10-7M
Calculate the Ka for the following equation, given that [H3O+]=4.6x10-3.Suppose we determine that it is a 0.100 M solution of HA.
HA(aq)+H2O(l)⇌H3O+(aq)+A−(aq)
[HA] (M) [A−] (M) [H3O+] (M)
(I) 0.100 0 0
(C) −x +x +x
(E) 0.100−x x 4.6x10−3
[HA]=(0.100−x)M =(0.100−4.6x10−3)M
= 0.0954 M
Ka=[H3O+][A-]/[HA]
=(4.6x10−3)(4.6x10−3)/(0.0954)
=2.21x10-4
Which of the following acids has the lowest % ionization in a 1.00M solution of the acid?
A. Ka=4.0x10-4
B. Ka=5.6x10-5
C. Ka=5.9x10-5
D. Ka=5.5x10-5
D. Ka=5.5x10-5
What is an Arrhenius acid?
H+ releaser
What is the Ka value of an acid with the Kb value of 7x10-15?
Ka+Kb=Kw
Kw=1x10-14
Kb=7x10-15
Ka=Kw-Kb
Ka=(1x10-14)-(7x10-15)
=3x10-15
What is the value of Kb if pKb=12.3?
Kb=10-pKb
Kb=10-12.3
=5.01x10-13
Given the reaction: (CH3)3N(aq)+H2O(𝓁) ⇌ (CH3)3NH+(aq)+OH−(aq). It is a 0.500M solution with a [OH-]=7.4x10-3. What is the value of Kb?
[(CH3)3N](M) [(CH3)3NH+](M) [OH-](M)
(I) 0.500 0 0
(C) -7.4x10-3 +7.4x10-3 +7.4x10-3
(E) 0.4926 7.4x10-3 7.4x10-3
Kb= [(CH3)3NH+][OH-]/[(CH3)3N]
=(7.4x10-3)(7.4x10-3)/(0.4926)
=1.11x10-4
Calculate the % ionization of something with the [BH+]equilibrium=3.28x10-4M and [B]initial=0.07M.
% ionization=[BH+]equilibrium/[B]initial x100%
% ionization= 3.28x10-4M/0.07M x100%
=0.46%
What is an Arrhenius base?
OH- releaser