Name the discontinuity:
The graph approaches infinity at the point of discontinuity
Infinite discontinuity
caused by a vertical asymptote
How do you simplify?
lim[f(x)g(x)]
as x approaches c
limf(x)·limg(x)
As x approaches c
What happens to the 5 in the problem
lim(5+4x+x3) x -> ∞
It is insignificant compared to the ∞ plugged in at x3 so it is dropped
lim(x2+3)
x -> 1+
4
If limf(x)=3 as x->c,
find lim[3f(x)]
9
What is a sign chart
A sign chart is a visualization used to find limits.
A line is drawn with markings at each zero and can be used to find if an infinite limit is negative or positive
YES
What is a good way to visualize infinite limits?
Draw a sign chart!
lim[(x2-6x+1)/(x+3)]
x -> -3+
∞
If limf(x)=4 at x->2 and limf(x)=3 and x->3
find limf(x)² as x->2
16
What is a Jump Discontinuity
A place where the left side limit and the right side limit of an equation do not match, so the graph cannot be continuous
TRUE OR FALSE?
lim[b·f(x)]=b·limf(x)
as x approaches c
TRUE
What is BOSTON?
A method commonly used to discover the presence of horizontal asymptotes. It refers to the degree of polynomials in numerator and denominator Bottom y=O Same a/b Top O N
lim(5+4x+x3)
x -> ∞
∞
find lim(2sinx⁄3x) as x->0
2/3
What is the Squeeze Value Theorem
If g(x) ≤ f(x) ≤ h(x) for all x in some interval about C AND limg(x)=limh(x)=L
THEN limf(x)= L at x=c
TRUE OR FALSE?
lim[f(x) ± g(x)] = limf(x)·limg(x)
as x approaches c
FALSE
limf(x) ± limg(x) as x approaches c
What is the limit of a function with a vertical asymptote at x=c as x approaches c from the left?
±∞
find lim(sinx) as x-> π/2
1
Is this function continuous?
x2-2, x<2
f(x)= x+3, x>2
No there is a jump discontinuity at x=2
3 Conditions for continuity at x=c
1. function is defined at x=c
2. right and left limits of c are equal (limf(c) exists
3. limf(x)=limf(x)=limf(x)=f(c)
x-> c x->c- x->c+
SIMPLIFY TO SOLVE
lim[f(x)/g(x)]
as x approaches c
limf(x) / limg(x)
IF limg(x)≠0 as x approaches c
What is the limit of sin(x) as x-> ∞
Why?
Does Not Exist (DNE)
It is an oscillating function so it does not get close to any one number as x approaches ±∞
My brother drives his car to school every day. Today, he went 60mph on Creedmor. Was his speed 45 at any point in time? Why?
Yes- His speed started at 0 and rose to 60. According to the intermediate value theorem, it must have passed through 45 mph at some point.
Find the limit as x->2
lim|x-2|/x-4
|0|/-2
=0