Derivatives
e and ln
Applications
100

x2 + 2x - 4

2x + 2

100

e2x

2e2x

100

f(t) = 700 - 11t2 represents the height of a sand dune in feet at a given time t (years).

What is the height of the dune initially?

When does the height of the dune reach 0?

*Include units*

f(0) = 700 ft

t (when f = 0) = 7.977 years

200

sqrt(x+ 2)

(2x3) / sqrt(x4 + 2)

200

ln(7x2 + pi)

(14x) / (7x2 + pi)

200

Given the equation for the position of an object at a given time t:

x(t) = t4 - 7t3 + (2/3)t - 2

Find the equations for velocity and acceleration in terms of time (v(t) and a(t)).

v(t) = 4t3 - 21t2 + (2/3)

a(t) = 12t2 - 42t

300

(x4 - 3x)(x + 4)2

(4x3 - 3)(x + 4)2 + 2(x4 - 3x)(x + 4)

300

2eln(e^(x^2))

4xe(x^2)

300

Write the equation for the population of a bacteria colony using P(t) = P0ert. Use t in terms of days.

The colony starts with 1000 bacteria and doubles in a day. 

P(t) = 1000eln(2)t

400

(x2 + 2) / (3x)

(2x(3x) - 3(x2 + 3)) / (3x)2

400

ln((6x) / (3x2))

-1/x

400

Find the rate at which water drains from a tank holding 2000 gallons at t = 3 minutes if the equation for volume at a given time (minutes) is:

V(t) = 2000(1 - (t/20))2

*Include units*

V'(3) = -170 gallons/min

500

((17x) / 4) * sqrt((x3 + 2)3)

(17/4)sqrt((x3 + 2)3) + ((17x) / 4) * (3/2)sqrt(x3 + 2)(3x2)

500

esqrt(x^2 + 2) * ln(sqrt(x))

(xesqrt(x^2 + 2)ln(sqrt(x))) / (sqrt(x2 + 2)) + esqrt(x^2 + 2) / (2x)

500

Calculate the marginal profit of 60 units if:

R(x) = 0.3x2 - 24x

C(x) = 2500 - 22x

*Include Units*

P'(60) = $34

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