Why are we already integrating?
int (8x+4x^3-6x^2) \dx
4x^2+x^4-2x^3+C
int (x*sqrt(x^2+5)) dx
(1/3)*(x^2+5)^(3/2) + C
int (x*e^x) dx
xe^x - e^x + C
int ((x^2+1)/4x) dx
(1/8)*x^2 + (1/4)*ln|x| + C
int (4x^3+2x^5+2) dx
x^4+(1/3)x^6+2x+C
int ((6x+15)*sqrt(x^2+5x)) dx
2(x^2 + 5x)^(3/2) + C
int (xe^(2x)) dx
(1/2)xe^(2x) - (1/4)e^(2x) + C
int (4x)/(x^2+1) dx
2*ln|x^2+1| + C
int (5x^4 + 3x - cuberoot(x) + 7) dx
x^5+ (3/2)x^2 - (3/4)x^(4/3) + 7x + C
int ((x^2)/(3*sqrt(x^3+4))) dx
(2/9)*(x^3+4)^(1/2) + C
int (sqrt(x)*ln(x)) dx
(2/3)*x^(3/2)*ln(x) - (4/9)*x^(3/2) + C
int (secx*tanx*e^(secx)) dx
e^(secx) + C
int (5 + pi - e^(2x) + 3^x) dx
5x + pi*x - (1/2)e^(2x) + (3^x)/(ln(3)) + C
int (x^3)/(x^2+5) dx
(1/2)*(x^2 + 5 - 5*ln|x^2+5|) + C
int (cosx*ln(sinx)) dx
sinx(ln*sinx - 1) + C
int 4/(x^2 + 1) dx
4*arctan(x) + C