The integral used to find the area bounded by y = 2^x , y = 8, and the y-axis. (Must include a sketch of the region)
What is
int_0^3 (8-2^x)dx
The integral used to compute the volume of the solid obtained by rotating the region enclosed by y = x^3 and y = 4x about the x-axis.
What is
pi int_0^2 (16x^2-x^6) dx = (512pi)/21
The integral used to find the volume of the solid obtained by rotating the region bounded by the graphs of y = sqrt(x), y = 2 − x and y = 0 around the y-axis. (You must sketch the region.)
pi int_0^1 [(2-y)^2-(y^2)^2]dy
Suppose a force of 10 N is required to stretch a spring 0.1 m from its equilibrium position and hold it in that position. How much work is needed to stretch the spring 0.25 m from its equilibrium position?
What is 3.125 J
The arc length of
y = ln(secx)
for
[0,pi/4]
What is
ln(sqrt(2) + 1)
The integral used to find the area bounded by y = 3^x , x = 2, the x-axis, and the y-axis. (Must include a sketch of the region.)
What is Int(3^x,x,0,2)
int_0^2 3^xdx
The integral used to compute the volume of the solid obtained by rotating the region enclosed by y = x^3 and y = 4x about y = -1.
What is
pi int_0^2 [(4x + 1)^2 - (x^3 + 1)^2]dx
The integral used to find the volume obtained by revolving the region bounded by y = x^2 − 4 and y = 4 − x^2 around the line x = 2? (You must sketch the region.)
What is
2pi int_-2^2[(2 - x)((4 - x^2) - (x^2 - 4))]dx
Set up an integral to find the surface area formed by rotating f(x) = sin(x), on the interval [0,pi] about the x-axis.
What is
2pi int_0^pi sin(x)sqrt(1 + cos^2(x))dx
The integral used to find the area in the first quadrant between x^2 + y^2 = 1 and x^(1/2) + y^(1/2) = 1. (Must include a sketch of the region.)
What is
int_0^1 (sqrt(1-x^2) - (1 - sqrt(x))^2)dx
The integral used to compute the volume of the solid obtained by rotating the region enclosed by y = x^3 and y = 4x about y = 9
What is
pi int_0^2 [(9 - x^3)^2 - (9 - 4x)^2]dx
The integral used to find the volume of the solid obtained by rotating the area between the graphs of y = x^2 and x = 2y around the y-axis. (You must sketch the region.)
What is Shell:
2pi int_0^(1/2) x(x/2 - x^2)dx
Washer:
pi int_0^(1/4) [(sqrt(y))^2-(2y)^2]dy
Find the center of mass for the region enclosed by
y = 4 - x^2
and the x-axis.
What is
(0,8/5)
The integral used to find the area between the curves y = cos(x) and y = 1/2 x - 1, bounded on the left by the y-axis. Use technology to find the point of intersection rounded to 3 decimal places. (Must include a sketch of the graph.)
What is
int_0^1.714 (cosx - (1/2 x - 1))dx
The integral used to compute the volume of the solid obtained by rotating the region enclosed by y = x^3 and y = 4x about the y-axis.
What is
pi int_0^8 [y^(2/3) - (y/4)^2]dy
Integral used to find the volume of the solid obtained by rotating the region between the graphs of y = x sqrt(2 - x) and y = 0 around the x-axis. (You must sketch the region.)
What is
pi int_0^2 x^2(2-x)dx
The integral used to find The area bounded by the curves y = x^2 - 4 and y ={ 1/2 x + 1 if x <= 0, -1/2 x + 1 if x > 0 (Must include sketch of graph)
What is Int((1/2 x + 1) - (x^2 - 4),x,-2,0) + Int((-1/2 x + 1) - (x^2 - 4),x,0,2)
int_-2^0 [(1/2 x+1)-(x^2-4)]dx+int_0^2 [(-1/2 x+1)-(x^2-4)]dx
The integral used to compute the volume of the solid obtained by rotating the region enclosed by y = x^3 and y = 4x about x = 2.
What is
pi int _0^8 [(2 - y/4)^2 - (2 - y^(1/3))^2]dy
The Integral used to find the volume formed by rotating the region enclosed by y = 2x - x^2 and the x-axis about the line x = -1. (You must sketch the region.)
What is
2pi int_0^2(x+1)(2x - x^2)dx