What is the
cos((3pi)/2)?
0
For the triangle shown, find
cos(theta) 
4/5
Convert to radians:
- 120o
(-2pi)/3
Set up a trig equation that can be used to solve: A 10 foot ladder propped up against a house makes a 25^0 angle of elevation with the ground. How tall is the top of the ladder from the ground?
sin(25^0) = x/10
1/sinx =
Find
sin ((5pi)/3)
-sqrt3/2
Find the missing side:

13.6
SET UP a trig equation to solve for the height of a streetlight, if there is an 8 foot shadow with a 25 degree angle of depression. You do NOT need to solve.
tan(25) = h/8
An foot ladder propped up against a house makes a 40^0 angle of elevation with the ground. How tall is the top of the ladder from the ground? Round to two decimal places.
5.14 feet
sin x/cos x =
tan (x)
sec(pi/4)=
sqrt2
Find cot(theta)

(3sqrt(7))/7
Solve: tan(x) = 1. 0<x<2pi
pi/4, (5pi)/4
An airplane is 30000 feet in the air and has an angle of depression of 15^0 as it approaches it's landing spot. What distance will the plane fly diagonally as it goes from this location to the landing spot? Round to the nearest foot.
1115911 feet
1 -cos^2x
sin^2x
csc (480o)
(2sqrt(3))/3
Find the missing angle. Round to the nearest degree.
35^0
Find
sec ((5pi)/3)
2
Solve on the interval [0, 2pi]
2 + sin ^2x = 3
x = pi/2, (3pi)/2
Prove:
(sinx)(1/cosx)(tanx) = sec^2x-1
(sinx)(1/cosx)(tanx) = sec^2x-1
(tanx)(tanx) = sec^2x-1
(tan^2x) = sec^2x-1
sec^2x-1 = sec^2x-1
cot((23pi)/6)
-sqrt3
A lifeguard sits in a chair that is 4 feet above the ground. She spots a swimmer in the ocean. The angle of depression from the lifeguard’s line of sight down to the swimmer is 15^0 . How far out horizontally is the swimmer from the shore? Round to the nearest tenth.
14.9 feet
Find
cot((13pi)/6)
sqrt3
Solve for x on the interval [0, 2pi] :
sinx -2sinxcosx = 0
x = 0, pi, 2pi, pi/3, (5pi)/3
Prove:
((cscx-1)(cscx+1))/cot (x) = cotx
((cscx-1)(cscx+1))/cot (x) = cotx
((csc^2x-1)/cot (x) = cotx
(cot^2x)/cot (x) = cotx
cot (x) = cotx