Midpoint and Distance
Pg 54, # 13
(6, 1)
Pg 201, # 13
y-4= 1/2 (x+2)
Pg 202 # 19
y-6=-3/2(x-6)
Pg 403 # 6
Scalene
pg 619, #10
20.3
Pg 54, # 23
18
Pg 202, # 24
No
Pg 202, #15
Yes
Pg 403 # 12
Square
pg 619, #16
3
Pg 54, #18
(0, -34)
Pg 202, #29
If that is the case, the lines are the same
Pg 203 # 37
Yes
Pg 403 # 16
Rhombus
Pg 619, #12
0.24
Pg 54, # 40
10, (1, 4)
Pg 203 #32
AB not parallel to CD
BC not parallel to AD
Pg 203 # 40
Responses will vary
Since the line perpendicular to the other two has, for example, a slope of a/b, then the slopes of the other two lines have to be -b/a. Since they are the same, they must be parallel.
Pg 416 #5
M(-a, b), N(a, b)
PN = RM = sqrt(9a^2 + b^2)
Pg 621, #32
24.5
Pg 55, #58a
(-10, 8), (-1, 5), (8, 2)
Pg 201 #8
If the lines are not parallel, find where the lines intersect
No,
(16, 8)
Pg 203 # 42
No
Pg 417, #22
An altitude is a parallel line from a vertex of a triangle to the opposite base. Using coordinate geometry, you should have shown that the intersection point of the altitude and the opposite side is the same point as the midpoint of that line
Pg 621, #43
12800