What is SLOPE-INTERCEPT FORM?
y=mx+b
What is POINT-SLOPE FORM?
y - y_1 = m(x - x_1)
What is STANDARD FORM of a linear function?
Ax + By = C
If two lines are parallel, then how do their SLOPES compare?
Their slopes are EQUAL (the same).
If two lines are PERPENDICULAR, then how do their slopes compare?
Their slopes are OPPOSITE RECIPROCALS (or their PRODUCT IS -1).
Identify the SLOPE and Y-INTERCEPT of the line:
y=2/3x-9
slope: 2/3
y-intercept: (0,-9)
Identify the SLOPE of the line:
y - 6 = -5(x + 8)
-5
To rewrite 7x - 8y = 16 in slope-intercept form, what would be your FIRST STEP?
Subtract 7x from both sides.
What is the SLOPE of a line that is parallel to
y = 5/3x + 11
5/3
What is the SLOPE of a line that is perpendicular to
y = 5/3x + 11 ?
-3/5
Rewrite the equation in SLOPE-INTERCEPT FORM:
y-5=-2(x+6)
y=-2x-7
Identify a POINT on the line:
y - 6 = -5(x + 8)
(-8,6)
Rewrite in slope-intercept form:
3x-2y=10
y=3/2x-5
What is the SLOPE of a line that is parallel to
3x + 6y = 18
-1/2
What is the SLOPE of a line that is perpendicular to 3x + 6y = 18 ?
2
Rewrite the equation in SLOPE-INTERCEPT FORM:
y-5=4/3(x+6)
y=4/3x+13
Write the POINT-SLOPE FORM equation of the line that has a slope of 3/4 and passes through (12, -5) .
y + 5 = 3/4(x - 12)
Identify the SLOPE of the line:
5x - 2y = 8
5/2
Write the point-slope form equation of the line that passes through (4, -3) and is parallel to y = 5/6x + 9
y + 3 = 5/6(x - 4)
Write the point-slope form equation of the line that passes through (4, -3) and is perpendicular to y = 5/6x + 9 .
y +3 = -6/5(x - 4)
Rewrite the equation in SLOPE-INTERCEPT FORM:
3x + 2y = 10
y = -3/2x + 5
Write the POINT-SLOPE FORM equation of the line that passes through (5, -2) and (-1, 3) .
y + 2 = -5/6(x - 5)
OR
y - 3 = -5/6(x + 1)
Find the coordinates of the Y-INTERCEPT of
5x + 4y = 40
(0, 10)
Write the point-slope form equation of the line that passes through (-5, 1) and is parallel to 4x - 2y = 10 .
y - 1 = 2(x + 5)
Write the point-slope form equation of the line that passes through (-5, 1) and is perpendicular to 4x - 2y = 10 .
y - 1 = -1/2(x + 5)