chemistry
2 C4H10 + 13 O2 → 8 CO2 + 10 H2O
What type of reaction is this?
combustion
16 Rb + S8 --> 8 Rb2S
What type of reaction is this?
combination (synthesis is ok too)
PtCl4 (s) --> Pt (s) + 2 Cl2 (g)
What type of reaction is this?
decomposition
2 C4H10 + 13 O2 → 8 CO2 + 10 H2O
Find the molar mass of each molecule in the equation.
C4H10 = 58.124 g/mole
O2 = 31.998 g/mole
CO2 = 44.009 g/mole
H2O = 18.015 g/mole
500 points per answer
16 Rb + S8 --> 8 Rb2S
Find the molar mass of each chemical in the equation.
Rb = 85.466 g/mole
S8 = 256.48 g/mole
Rb2S = 202.992 g/mole
PtCl4 (s) --> Pt (s) + 2 Cl2 (g)
Find the molar mass of each chemical in the formula.
PtCl4 = 336.88 g/mole
Pt = 195.08 g/mole
Cl2 = 70.90 g/moles
2 C4H10 + 13 O2 → 8 CO2 + 10 H2O
How many moles of carbon dioxide are made from 0.2824 moles of C4H10?
1.130 moles CO2
16 Rb + S8 --> 8 Rb2S
How many moles of Rb are needed to make 0.392 moles of Rb2S?
0.196 moles Rb
PtCl4 (s) --> Pt (s) + 2 Cl2 (g)
How many moles of PtCl4 are needed to make 0.982 moles of chlorine gas?
0.491 moles PtCl4
2 C4H10 + 13 O2 → 8 CO2 + 10 H2O
How many grams of water are made from 0.103 moles of C4H10?
9.28 g H2O
16 Rb + S8 --> 8 Rb2S
How many grams of Rb2S are made from 0.0150 moles of S8?
24.4 g Rb2S
PtCl4 (s) --> Pt (s) + 2 Cl2 (g)
How many grams of PtCl4 are needed to make 0.2914 moles of Cl2?
49.08 g PtCl4
2 C4H10 + 13 O2 → 8 CO2 + 10 H2O
How many grams of CO2 is made from 15.00 grams of C4H10?
45.43 g CO2
16 Rb + S8 --> 8 Rb2S
How many grams of Rb are needed to use up 54.5 grams of S8?
290.6 g Rb
PtCl4 (s) --> Pt (s) + 2 Cl2 (g)
How many grams of Pt are made from 525.0 grams of PtCl4?
304.0 g Pt
2 C4H10 + 13 O2 → 8 CO2 + 10 H2O
The reaction takes place in a 10.0 L container at 550 degrees C and 2.50 atm.
(a) Find the number of moles of C4H10 in the reaction container at those conditions.
(b) How many liters of CO2 is made from that amount of moles of C4H10? Assume the pressure and temperature are both constant. Use only the moles of CO2 to find the V for CO2.
(a) 1.48 mole CO2
(b) 40.0 L CO2
300 points per answer
16 Rb + S8 --> 8 Rb2S
How many grams of Rb2S is made from 125.0 grams of Rb?
148.4 g Rb2S
PtCl4 (s) --> Pt (s) + 2 Cl2 (g)
The reaction takes place in a 750 mL container at 25 degrees C and 2.5 atmospheres.
What is the volume of Cl2 produced from 225.0 g of PtCl4? Hint: use ideal gas law to solve for V (using moles of Cl2).
17.4 L Cl2