type 1
type 2
type 3
type4
type5
100
Product of two functions
. The Leibnitz theorem is the formula to find the nth derivative of
100
) (log5)^2 e^(log5)x
The nth derivative of 5^x is
100
function of x
To find the nth derivative of a function y=f(x) its (n-1) derivatives must be
100
((-1)^n (n+21)!)/(2! (x+2)^(n+3) )
The n^th derivative of 1/(x+2)^3
100
0
If y=(ax+b)^mwith m=nthen y^n is
200
((-1)^n n!〖 2〗^n)/(2x+3)^n
If y=log⁡(2x+3), then y^n is
200
function of y
To find the nth derivative of a function y=f(x) its (n-1) derivatives must be
M
e
n
u