Quadratic Equations
x2=x+6
x=-2,3
What value or values of x make the denominator 0?
(x+5)/(x+8) =1+ 6/(x+1)
x≠-8,-1
25x+19-10x=-11+5x
x=-3
5-8|-2x|=-75
x=-5,5
-3+6i-(-5-3i)-8i
2+i
2x2+5x+3=0
x=-3/2,-1
(x−4)/5x = 1/5x +2
x=-5/9
3x+2(x-6)=33
x=9
x=-15,-1
(1-7i)2
-48-14i
3x2-15x-42=0
x=-2,7
2 = √(4x)
x=1
(9+7x)/3=-11
x=-6
|7x+4|/8=3
x=-4, 20/7
(8-6i)(-4-4i)
-56-8i
3x2=36
x=+-2√3
x=√(42-x)
x=6
−6≥-5x+5+4
3≤x
|x-4|/5≤ 2
-6≤ x≤ 14
or
[-6,14]
6(-7+6i)(-4+2i)
96-228i
x2-6x+25=0
x=3+-4i
x=-1,4
x−15>−4(−6+3x)
x>3
8+|4x-7|≥ 17
x≥ 4, x≤ -1/2
or
[-∞,-1/2]U[4,∞]
(2+i)/(3-i)
1/2+1/2i