Is this function growing or decaying?
y = 2(1/3)x + 1
Decay
Rewrite the equation in logarithmic form.
289-1/2 = 1/17
log289(1/17) = -1/2
Expand the logarithm:
log9(ab3)
log9(a) + 3 log9(b)
Solve the equation:
log12(3m - 10) = log12(14)
log12(3m - 10) = log12(14)
3m - 10 = 14
3m = 24
m = 8
Determine if the sequence is geometric. If it is, find the common ratio, the term named in the problem, and the explicit formula.
-2, -6, -18, -54, ...
Find a12
r = 3
a1 = -2
an = -2(3)n-1
a12 = -2(3)12-1
a12 = -354,294 yes, geometric
Is this function growing or decaying?
y = 3x-2-2
Growth
Rewrite the equation in exponential form:
log7(49) = 2
72 = 49
Expand the logarithm:
log8 (x4/y)
4 log8(x) - log8(y)
Solve the equation:
4-k - 2 = 16
4-k - 2 = 16
4-k - 2 = 42
-k - 2 = 2
k = -4
Determine if the sequence is geometric. If it is, find the common ratio, the term named in the problem, and the explicit formula.
-3, 6, -12, 24, ...
Find a9
r = -2
a1 = -3
an = -3(-2)n-1
a9 = -3(-2)9-1
a9 = -768 yes, geometric
Identify the initial value, whether the change represents growth or decay, and find the percentage rate of increase or decrease:
y = 1800 ⋅ 0.85x
a = 1800
Decay (0.085 < 1)
r = 1- 0.85 = 0.15 ⋅ 100 = 15%
Evaluate the expression:
log3(243)
3x = 243
3x = 35
x = 5Condense the expression to a single logarithm:
12 log9(x) - 4 log9(y)
log9(x12/y4)
Solve the equation:
log20(80 + n) = log20(n2 + 3n)
log20(80 + n) = log20(n2 + 3n)
80 + n = n2 + 3n
0 = n2 + 2n - 80
0 = (n + 10)(n - 8)
n = -10, 8
Evaluate the geometric series described:
-4 - 8 - 16 - 32..., n = 8
a1 = -4
r = 2
an = -4(2)n-1
∑ (-4(2)x-1) = -1020
Identify the initial value, whether the change represents growth or decay, and find the percentage rate of increase or decrease:
y = 4200 ⋅ 1.603x
A = 4200
Growth (1.603 > 1)
r = 1.603 -1 = .603 x 100 = 60.3%
Evaluate the expression:
log5(125)
5x = 125
5x = 53
x = 3
log5(u) + log5(v) + 5 log5(w)
log5(uvw5)
Solve the equation:
52n = 5-2n
52n = 5-2n
2n = -2n
4n = 0
n = 0
Evaluate the geometric series described:
1 - 3 + 9 - 27..., n = 7
a1 = 1
r = -3
an = 1(-3)n-1
∑ (1(-3)x-1) = 547
A new social media site is increasing its user base by approximately 6% per month. If the site currently has 37,480 users, what will the approximate user base be 7 months from now?
a = 37,480
r = 0.06
t = 7
y = 37,480 (1 + 0.06)7 = 56,356 users
Use a calculator to approximate the log to the nearest thousandth:
log6(49)
(log 49)/(log 6) ≈ 2.172
Condense the expression to a single logarithm:
log7(2) + log7(11) + 4 log7(3)
log7(2 ⋅ 11 ⋅ 34) = log7(1782)
Solve the equation. Round your answer to the nearest thousandth.
9 ⋅ 11k = 51
9 ⋅ 11k = 51
11k = 17/3
log11(17/3) = k
k ≈ 0.723
log7(24)
(log 24)/(log 7) ≈ 1.633