Find f(2).

This domain of this relation, makes it a function. (Yes or No?):
{(7,2), (6,4), (5,2), (8,3), (7,4), (9,5)}
NO, the number seven in the domain maps to two elements in the range.
What is the inverse of the point (-1,3)?
Final answer: (3,-1)
Given g(x) = x + 2
What is g(2)?
g(2) = 4
Is this function odd or even?

Even (has symmetry along the y-axis)
Does this graph have an absolute or relative minimum? If so, what are they?

Find f(g(6)).

f(g(6)) = f(7)
f(7) = 1
Final answer: f(g(6)) = 1
What is the range of this function:

(0, ∞)
Find the inverse of the function: f(x) = 2x
This inverse is: f-1(x) = x/2
Given f(x) = x - 6
What is f(a2+1)?
f(a2+1) = (a2 +1)- 6
Final answer: f(a2+1) =a2-5
Is this function odd or even?

Odd (symmetric about the origin)
Does this graph have an absolute maximum?

Yes
Given: f(x) = -5x+6 and g(x) = 2x2-x
Find f(g(x)).
f(g(x)) = -5(2x2-x)+6
Final answer: f(g(x)) = -10x2 + 5x + 6
What is the domain AND range of this function:

Domain: [-2,1]
-2 ≤ x ≤ 1
Range: [0,3]
0 ≤ y ≤ 3
Given the function: f(x) = {(-1,2), (4,7), (6,11), (8,9)}
What is the domain of the inverse function?
The domain of the inverse function is:
{2,7,9,11}
Given, f(x) = 3x - 5 and g(x) = x2
What is (f+g)(x)?
f(x)+g(x)
3x-5 + x2
Proper form: x2+3x-5Determine if this function is odd or even?

On what interval(s) is this graph decreasing?

The graph decreases on the interval (-2,2).
Find g(f(-1))
f(x) = 1/x+2, g(x) = 2x-5
g(f(x)) = 2(1/x+2)-5
Final answer: -3
What is the domain of this function:

All real numbers, x ≠ 3
Find the inverse of the function: g(x) = 3x - 9
Simplify completely.
Final answer: f-1(x) =
x/3+3
Given f(x) = 3x -5 and g(x) = x2
What is (f·g)(x)?
f(x)*g(x)
(3x-5)(x2)
Final answer: 3x3-5x2
Determine if this is an even or odd function.

Even function (y-axis symmetry)
Does this graph have absolute or relative maxima? If so, what are they?

Does NOT have absolute maxima.
DOES have relative/local maximum at (-6,2)
Given: f(x) = ½ + x,
g(x) = 1/x2- 2x, h(x) = 5x-1
Find f(h(½)) and h(g(-3)).
f(h(x)) = ½ + 5x - 1
Final answer 1: f(h(½)) = 2
h(g(x)) = 5((1/x2) - 2x) - 1
Final answer 2: h(g(-3)) = 29.56
What is the domain AND range of this function:

Domain: (-∞ , -1] and (-1, ∞ )
x≤ -1 and x > -1
Range: (-3, ∞)
y > -3
Verify that the two functions are inverses:
f(x) = 2x + 6 and g(x) = 1/2x - 3
Yes they are inverses.
Given p(n) = n2+n+1.
Find p(a-3).
p(a-3) = (a-3)2 + (a-3) + 1
p(a-3) = a2-6a+9 + a-3 + 1
p(a-3) = a2 - 5a + 7
Determine if this function is odd or even.

This function is NEITHER. (No symmetry about the y-axis or origin)
On what interval(s) is the graph increasing?

The graph is increasing on three intervals:
(-2,-1) U (2,4) U (6,7)
Given: f(x) = 2x, g(x) = x2-2x,
h(x) = 1/x^2
Find g(h(f(-6))).
g(h(f(x))) = ¹⁄₆₄x⁴ − ¹⁄₄x²
Final answer: g(h(f(-6))) = -0.0069..
Find the domain of this function:

All real numbers, x ≥ 2, x ≠ 5
Show that each function is an inverse of one another:
f(x) = 5x - 8 and g(x) = (x+8)/5
Show Ms. Sanderson your work :)
Given C(t) = ¹⁄t + 2 and N(t) = t2 + t + 1
Find (C-N)(2).
C(t) - N(t)
(¹⁄t + 2 ) - (t2 + t + 1)
¹⁄t + 2 - t2 - t - 1
(C-N)(2) = -4.5
Determine if this is an odd or even function.

NEITHER (no symmetry about the y-axis or origin)
ITS NOT A FUNCTION.
Are there any relative or absolute minima and maxima in this graph? If so, what are they?
When is the graph constant?

There are relative AND absolute minima and maxima.
Relative minimum: (6, -1)
Absolute minimum: (2, -2)
Relative maximum: (-1, 1)
Absolute maximum: (4, 2)
The graph is NEVER constant (flat).