What is the base value in the following exponential equation:
42=16
4
What formula should be used for the following equation:
Lisa invested 2,000 in an account at an 1.8% interest rate compounding continuously for 10 years
A = Perrt or A=2,000e0.018*10
Solve for be rounding to the nearest hundredth:
3b= 17
*Remember, in order to solve a variable trapped in the exponent, you must use LOGS!
2.58
Expand this Log:
log(3x4y7)
log(3) + 4log(x) +7log(y)
Solve:
log (5x) = log (2x + 9)
3
Change the following equation from logarithmic to exponential:
log5125=3
53=125
Write an equation to model the following situation:
Mark invested 20 in an account at an 7% interest rate compounding bimonthly for 15 years
f(x)=20(1+(.07/24))24*15
or
f(x)=20(1.0029)360
Solve for x round to the nearest tenth:
5 ⋅ 186x = 26
0.1
Simplify this Log:
2log4(x) + 5log4(y) - 1/2log4(z)
log4(x2y5 / z1/2)
Solve and give your answer as a fraction:
−2log5 (7x) = 2
1/35
List the type of function as well as the transformations of the following exponential equation compared to its parent function:
f(x)=-2(3)x-4+5
Exponential growth
Reflected over x axis
Stretch of 2
Right 4
Up 5
Becky invested $19,800 in a CD that pays an interest rate of 5.3%. The CD is set to compound daily. How much is in Becky’s account after 9 years?
$31,901.32
Solve for n rounding to the nearest hundredth:
16n-7+ 5 = 24
8.06
Expand this Log (keep as ln):
ln(4x3/y)
ln 4 + 3 ln x - ln y
Solve:
−6log3 (x − 3) = −24
84
Convert the logarithmic function to exponential
Ln 27=x
ex=27
Jack bought a new car in 2014 for $28,000. If the value of the car decreases by 14% each year what will be the difference of value of the car be in 2025.
28,000-5,328.94=
22,671.06
solve for x
log3(2)+2log3(x)=log3(7x-3)
x=1/2 and x=3
Simplify this Log:
7 ln x + 2 ln y
ln (x7y2)
Solve:
log10 (2) + log10 (x) = 1
5
List the transformations and the asymptotes of the following equation:
f(x)=1/4log6(x+3)+4
Log growth
compression 1/4
left 3
up 4
Vertical asym x=-3
A savings account balance is compounded continuously. Find the interest rate per year if the initial balance was $1,854.00 and it sat in an account for 5 years totaling to $2,154.04?
1854e0.03 x 5 ≈ $2,154.04
Solve for x:
32x=27x-4
x=12
Double Jeopardy
Jon invested $5,000 dollars into an account with an interest rate of 15% compounded continuously. Approximately how long will it take the investment to triple?
7 years
The half-life of a radioactive isotope is 4 days. If 3.2 kg are present now, how much will be present after 4 days?
1.6kg