Collecting Like Terms
Expanding Brackets
Solving Backwards
Multiplying/Dividing Terms
Substitution
100

3x + 5x

8x

100

2 (y + 4)

2y + 8

100

a+10=13

a=3

100

2 x a x 4 x b

8ab

100

a - 10 when a=21

11

200

7a + 2a - 4a

5a

200

3( 2a + 5)

6a + 15

200

3a=30

a=10

200

2 x a x c x a

2a2c

200

5a-12 when a = 3

3

300

7a + 2a +5b

9a + 5b

300

f (4d + 7)

4df + 7f

300

2a+11=25

a=7

300

3 x 12 x 2 x d x h

72dh

300

5a - 2b + 3 when a = 4 and b= 7

9

400

9a - 5a + 3b - b

4a + 2b

400

j ( j - 6)

j2 - 6j

400

3a-12=6

a=6

400

a5 / a3

a2

400

a + bc when a = 10, b = 9 and c=3

37

500

7a - 6b + a + 3b

8a - 3b

500

3e(2e+4a)

6e2 + 12ae

500

5(a-4)=20

a=8

500

a5b3/b5

a5/b2

500

ad + 2 - bc when a = 12, d = 5, b = 11, c = 2

40

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