9 ÷ ? = −9
-1
8 ÷ (−2)
-4
−27 ÷ ? = −9
3
36 ÷ ? = 9
4
−10 ÷ (−2)
5
−18 ÷ ? = 9
-2
2(−2)
-4
prime factors
270
2 x 3 x 3 x 3 x 5
2 x 33 x 5
120
2 x 2 x 2 x 3 x 5
23 x 3 x 5
1 + 2
3
Common prime factors
32 48
2 x 2 x 2 x 2 x 2 2 x 2 x 2 x 2 x 3
common pf- 2 x 2 x 2 x 2
12 15
GCF
2x2x3 3x5
3x3=9
gcf 9
Did you write your name on your paper
....
prime factors 81
3 x 3 x 3 x 3
34
2(60 – 20 ÷ 4)
2(60 – 20 ÷ 4) =
2(60 – 5) =
2(55) = 110
72 110
2x2x2x3x3x3
2x5x11
cpf 2
2 + 7.5 · 2²
2 + 7.5 · 2² =
2 + 7.5 · 4 =
2 + 30.0 =
32

3(6)2 - 12/4
3(36) - 12/4
108 - 3
105
15 + (8-3) / 2
15 + 5 / 2
20 / 2
10

5 / 3 -1/2(6) + 3
5 -3 +3
5
(1.5 · 2)2
(1.5 · 2)2 =
(3)2 = 9
2³ × 4¹ × 3²
2*2*2*4*3*3
288

2 + 7.5 x 4
2 + 30
32
275 – (32 – 7)(2) – 12
275 – (32 – 7)(2) – 12 =
275 – (25)(2) – 12 =
275 – 50 – 12 =
225 – 12 =
213
1/2(250) – 10²
1/2(250) – 10² =
1/2(250) – 100 =
125 – 100 = 25
There will be 30 adults and 24 children at the event next week. Find the number of tables that will be needed.
How many adults/kids at each table?
6 tables
5adults 4kids
3(4 + 2)² – 12/4
3(4 + 2)² – 12/4=
3(6)² – 12/4=
3(36) – 12/4=
108 – 12/4=
108 – 3 =
105
(5 + 2)² + 12 ÷ 2
(5 + 2)² + 12 ÷ 2 =
(7)² + 12 ÷ 2 =
49 + 12 ÷ 2 =
49 + 6 =
55
5 + [3(2 + 4)]²
5 + (3)(2) + 4]²
[5 + 6 + 4]²
[15]²
15 ÷ 3 – 1/2(6) + 3
15 ÷ 3 – 1/2(6) + 3 =
5 – 1/2(6) + 3 =
5 – 3 + 3 =
2 + 3 =
5
7 x 9 + 3 - 6 / 2 + 22 - 11
7 x 9 + 3 - 6 / 2 + 4 - 11
63 + 3 - 3 + 4 -11
66 - 3 + 4 - 11
63 + 4 - 11
67 - 11
56
In the expression 2³ · 15 – (8 + 14), what would be the first step when solving? The last step when solving?
The first step would be to solve inside the parentheses. The last step would be subtraction.
2³ · 15 – (8 + 14) =
2³ · 15 – 22 =
8 · 15 – 22 =
120 – 22 = 98
(16 - 24)2 + 3 x 11 - 1
(-8)2 + 3 x 11 - 1
64 + 3 x 11 -1
64 + 33 - 1
97-1
96
15+(8-3)/2
15+(8-3)/2
15+5/2
20/2
10
8 + (12 – 9)³ + (22 – 15)
8 + (12 – 9)³ + (22 – 15) =
8 + 3³ + (22 – 15) =
8 + 3³ + 7 =
8 + 27 + 7 =
35 + 7 = 42