Distributive Property
Bedmas
Solving Equations
Fractions
Collecting Like Terms
100

2(x+3)

2x+6

100

8+2×5

18

100

x+4=11

x=7

100

1/4 +2/4

3/4

100

3x+5x

8x

200

4(a−5)

4a−20

200

(6+4)×3

30

200

3x=21

x=7

200

5/6-1/6

2/3

200

7y+2−4y+5

3y+7

300

−3(2x+4)

−6x−12

300

20−12÷3

16

300

y−9=5

y=14

300

3/5 x 10

6

300

9a−3b+4a+2b−5

13a−b−5

400

5(2y−1)+3

10y−2

400

5(3+2)−7

18

400

2a+6=18

a=6

400

2/3 +1/6

5/6

400

6m+4n−2m+3−7n+8

4m−3n+11

500

2(x+4)−3(x−1)

−x+11

500

24÷(2+4)+6×2

16

500

5x−7=18

x=5

500

3/4 + 5/8 -1/6

29/24 or 1

500

12x−5y+7−3x+8y−4+2x−y

11x+2y+3

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