What is the complex conjugate of -100i ?
100i
Just change the sign on the imaginary portion!Simplify: (3-2i) - (7-4i)
-4+2i
Simplify:
5i(6+7i)
35+30i
Divide and Simplify:
(5+6i) / (4i)
(6-5i) / 4
Solve for x; must check for extraneous solutions:
(sqrt 3x-2) - 7 = 0
x=17
Simplify:
(7-5i) -2 + (10-4i)
15-9i
Simplify:
3(8-2i)
24-6i
Simplify:
(9-3i)(1-3i)
-30i
Divide and Simplify:
(2-5i) / (5i)
(-5-2i) / 5
Solve for x; must check for extraneous solutions:
4(sqrt x) - 5= 27
x=64
What is the complex conjugate of -7+6i ?
-7-6i
Simplify:
(8i) - (2i) +3 - (2i)
3+4i
Divide and Simplify:
(2-i) / (3+i)
(1-i) / 2
Solve for x:
x2 -4x +10 = 0
2+/- i (sqrt 6)
(sqrt x+1) = x - 1
x=3
and
x=0 <-extraneous
What does -6+7i2 simplify to?
-13
Simplify:
(10-2i)(2+4i)
28+36i
Simplify:
(-2+4i)(-9-5i)
38-26i
Solve for x and Simplify:
x2 +8x + 20 =0
-4 +/- 2i
(sqrt 7x-1) = (sqrt 5x +5)
x = 3
Simplify:
100 - (-10i + 6) + (4i - 5)
89+14i
Simplify:
213i - (5 - 10i) - (2i2)
-3 + 223i
Divide and Simplify:
(8) / (4+2i)
(8-4i) / 5
Solve and Simplify:
3x2 +6x + 7=0
[-3 +/- 2i (sqrt 3)] / 3
(sqrt 9-3x) = (3-x)
x=0
and
x=3