Order of Operations
Two-Step Equations
Parallel Lines
Polynomials
Systems of Equations
100

4(2 + 3 - 1) / 2

8
100

2x + 3 = 11

x = 4
100

What is the slope of a line parallel to

y = -4x + 16

-4
100

(x + 4)(x - 3)

x^2 + x -12

100
On a graph, how many solutions are there for parallel lines? 
No solutions
200

6 + 2 (3 - 1) - 1

9
200

-y - 3 = 8

y = -11

200

What is the slope of the line parallel to

-18x + 6y = -12

m = 3
200

(2n + 2)(6n + 1)

12n^2 + 14n + 2

200
Are there one, none, or infinitely many solutions to the linear equations, explain your answer:

y = -2x + 1

y = 3x -1

One solution, they have different slopes so they will cross on a graph.
300

40 / 2^2 - (5 - 3)

8
300

14 + h/5 = 2

h = -60

300

Are the graphs of the lines in each pair of equations parallel? Explain why or why not.

y = -1/2x + 3/2 and 5x - 10y = 15

No, the slopes are different.

300

(5q + 7 + 8q^3) + (4q^3 + 3 - 2q^5)

-2q^5 + 12q^3 + 5q + 10

300

Are  there one, none, or infinitely many solutions to the linear equations, explain your answer:

y = -3x + 2

6x + 2y = 4

Infinitely many, they are the exact same line.
400

(1 - (3 + 5))(2^2 - 3) + 2

-5
400

3 = 6/x

x = 2

400

Are the graphs of the lines in each pair of equations parallel? Explain why or why not.

y = 1/3x + 3 and x - 3y = 6

Yes, they have the same slope of 1/3

400

(4x^4 + x^2 - 2) - (x^4 - 3x^3 + 2x^2)

3x^4 + 3x^3 - x^2 - 2

400
Is (-1, 5) a solution to the set of linear equations? Be able to explain your answer.

y = 2x + 7

y = x + 6

Yes, the point (-1, 5) is a solution to both equations meaning the lines both pass through that point on a graph. 
500

-4 - (1 - 5) - (-4)^2

-16
500
4 = 24/x
x = 6
500

Write an equation for a line that crosses through point (2, 4) and is parallel to equation y = 3x + 7?

y = 3x - 2

500

(12^5 - 6a - 10a^3) - (10a - 2a^5 - 14a^4)

14a^5 + 14a^4 - 10a^3 - 16a

500
Graph the linear equations and determine whether there are is one, none, or infinitely many solutions to the equations

y = -2x - 1

y = -2x + 2

No solution, see overhead for graph.
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