Given the Roots
Standard Form
How Many Roots
Solve Using QF
Solve by Factoring
Solve by Square Roots
100

Given the roots -5 and 3 and the point ( -1 , -4 )

write the equation in factored form

-4 = a (-1 + 5 ) (-1 -3 )

-4 = a ( 4 ) ( -4 ). ; a = 1/4

y = 1/4 ( x +5 )(x - 3 )

100

Factored Form is y = 3/4 ( x + 1 ) ( x + 1 )

y = 3/4 ( x^2 +2x +1 )

y = 3/4 x^2 + 3x/2 + 3/4

100

5x^2 + 2x -7 = 0

(2)^2 -4(5)(-7)

discriminant = 144  2 real rational roots

100

x^2 + 7x -3 = 0     round to 2 decimals         

x= 0.41


x = - 7.41

100

6x^2 +x -1 = 0

( 2x + 1 )(3x - 1 )

x = -1/2      x = 1/3

100

3x2= 60

x = +sqrt20

x = -sqrt 20

200

Given the roots 5 and -3 and the point ( 4 , 4 )

write the equation in factored form

4 = a ( 4- 5 )(4 + 3 )

4 = -7a       ; a = -4/7

y = -4/7 ( x - 5 )( x + 3 )

200

Factored Form is y = -2 ( x - 5 )( x + 4 )

y = -2 ( x^2 -x -20 )

y = -2x^2 +2x +40

200

-5x^2 + 2x -7 = 0

( 2 )^2 -4 (-5)(-7)

Discriminant = -136.     0 real roots which is 2                                                complex roots

200

2x^2  + 5x =0

-5 + (sq rt of 25) / 4              0

-5 - ( sq rt of 25 ) / 4              -5/2

200

4x^2 - 25x +6 = 0

( 4x - 1 )(x-6)=0

x = 1/4        x= 6

200

(x+1/2)2 = 9/4

x= - 1/2 +3/2 =1

x =- 1/2 - 3/2 = -2

300

Given a double root of 7 and the point ( -9, -8 ), write the equation in factored form.

-8 = a ( -9 - 7 )(-9 - 7 )

-8 = 256a     ; a = -1/32

y = -1/32 ( x-7 )( x - 7 )

300

Factored Form is y = - ( x -0 )(x- 1 )

y = - ( x^2 -x )

y = -x^2 + x

300

9x^2 - 6x +1= 0

(-6)^2 -4 (9)(1)

discriminant = 0.            1 real rational root

300

5x^2 = 36

5x^2 - 36 =0

0 + ( sq rt of 720 ) / 10             2.68


0 - ( sq rt of 720 ) / 10               - 2.68

300

3x^2 = 108

3x^2 - 108=0

3 ( x^2 - 36 )=0

3 ( x+6)(x-6)=0

x=6         x= -6

300

8x2-8 = 120

x2= 128/8

x2=16

x=4 ; x=-4

400

Write the equation that passes through the points

( 6,0 )   ( 12,0 ) and ( 9,6 ) in factored form

6 = a ( 9-6 )(9-12)

6 = -9a ;         a = -2/3

y = -2/3 ( x -6 )( x - 12 ) 

400

Factored Form is 1/2 ( x + 5 )(x +5 )

y = 1/2 ( x^2 +10x +25 )

y = 1/2 x^2 +5x + 25/2

400

Explain in a few words why there are no roots when the discriminant is a negative number.

You cannot take the square root of a negative number.

400

5x^2 -27x + 10 = 0

27 + ( sq rt of 529 ) / 10            5


27 - ( sq rt 0f 529 ) / 10           2/5

400

2x^2 -10x +14 = 2

2x^2 -10x +12 =0

2 ( x^2 -5x +6 )=0

2 ( x-2)(x-3)=0

x =2         x=3

400

-1 - 4x2 = - 357

4x2= 356

x2= 356/4

x2=89

x = +sqrt89

x= - sqrt89


500

Write the equation in factored form that has roots of 

3/2       and       -5/2          and passes through the 

point ( 1 , 6 )

6 = a ( 1- 3/2 )( 1+ 5/2 )

6 = a (-1/2)(7/2 )

6 = a ( -7/4 ) ;    a = -24/7

y = -24/7 ( x - 3/2 )( x+ 5/2 )

500

Factored Form is y = 1/3 ( x-6 )( x +6 )

y = 1/3 ( x^2 - 36 )

y = 1/3 x^2 - 12

500

-3x^2 = -5x -18

( -5 )^2 -4 (3)(-18)

discriminant = 241        2 real irrational roots

500

-x^2 + 6x -15 = 0

-6 + ( sq rt of 96 ) / -2          -1.90


-6 - (sq rt of 96 ) / -2              7.90

500

14x^2 - 3 = -x

14x^2 +x -3 = 0

( 7x-3 ) ( 2x +1 )=0

x = 3/7      x = -1/2

500

3x2+7=37

x2=10

x = +sqrt 10

x = -sqrt 10

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