If the vertex of a parabola is (265,89) what is the maximum height and the time at the max-height
Max height: 89
Time at the max-height:
Calculate the vertex:
y=2x2=4x-3
(-1,-5)
y=2x2+5x+20
No Solution
y= √x
x y
0 0
1 1
4 2
9 3
16 4
√45
3
42
Identify the y-intercept
y=3x-6x+2
y-intercept:0,2
y=2x2-12x+18
1 Solution
y= √x+2
x y
-2 0
-1 1
2 2
7 3
14 4
√140
2√35
How long would it take the object to hit the ground using h=-16t2=76t?
4.75
Identify the y-intercept and the point of symmetry:
y=2x2-8x-4
y-intercept: (0,-4)
point of symmetry: (4,-4)
2x2-5x=-7
No Solution
y= √x-3
x y
3 0
4 1
7 2
12 3
19 4
√2 x √14
2√7
What are the Domain and range of the h=-16t2+76t?
Domain: 0 ≤ x ≤ 4.75
Range: 0 ≤ y ≤ 90.25
Using the vertex and the y-intercept, find the domain and range
Vertex: (2,-3)
Y-intercept: (0,1)
Domain: all real numbers
Range: y is greater than or equal to -3
5x2+21x=-18
x=-2,-1.2
y= √x-4
x y
4 0
5 1
8 2
13 3
20 4
5√2 x√24
20√3
How long does it take the object to reach the max height? Using h=-16t2+76t
2.375seconds
Calculate the vertex and y-intercept
y=2-8x+6
Vertex=(2,-2)
y-intercept= (0,6)
x2-15=2x
5,-3
y=3 √x-2
x y
4 0
5 1
8 2
13 3
20 4
√432
12√3