Unit circle application
Solve sin 90=
1
Solve cot(0) x sin(0)=
cos(0)
Solve sin(x) + 2 = 3 over the interval 0° ≤ x < 360°
90 degrees
4cos^2x−1=0
x=pi/3 or (pi-pi/3) or (pi+pi/3) or (2pi-pi/3)
What is the midline of a graph?
It is parallel to the x-axis and is located half-way between the graph's maximum and minimum values.
Solve tan (-pi/4)=
-1
Solve 1−cos^2x=
sin^2x
Solve tan2(θ) + 3 = 0 on the interval 0° ≤ θ < 360°
No Solution
cos^2+9cos+18=0
Not possible
Find the amplitude of a graph that has a midline of 0 and a maximum of 5
5
If 0∘≤θ<360∘ solve the following sinθ=0
0 degrees and 180 degrees
Solve csc^2x-1=
cot^2x
Solve cos(-x)=-sin^2x-cos^2x when 0 ≤ x ≤ 360
180 degrees
2sin^2x+3cosx-3=0
x=pi/3,5pi/3 x=0
When would you use a graph and determine the midline in the real world?
In a business when you want to find the middle point where every customer is happy and product sales are high