What is the chain rule formula?
(f(g(x)))' = f'(g(x)) * g'(x)
What does 'C' mean in the solution to an integral?
constant of integration - we could add any number there and get the same answer
How does a particular solution vary from a general solution?
A particular solution does not have a C. You use an initial value, or given value, to solve for C.
∫e2x dx
(1/2)e2x + c
What is the product rule formula?
d/dx f(x) * g(x) = f'(x)g(x) + f(x)g'(x)
d/dx [x2 - 3x]5
5[x2 - 3x]4 * (2x - 3)
What is the difference between a definite and indefinite integral?
Definite integrals are evaluated over a certain region - usually called limits of integration.
x' = 3t2 + 2t
x(0) = 3
x = t3 + t2 + 3
∫sinh(2x) dx
f(x) = x10
f'(x) = 10x9
d/dx [sin(6x)]
6cos(6x)
What are the bounds of integration here?
∫220 √[4x2 + 25x + 11]
lower bound is 2; upper bound is 20
x' = 1/t
x(1) = 1
x = ln(t) + 1
∫e-xx + e-xx2 dx
-e-x(x2+3x+3) + c
f(x) = sin(x)
f'(x) = cos(x)
d/dt [ln(x(t) - 2)]
x'(t)/(x(t) - 2)
d/dt [x(t)] = 3
x(t) = 3t + c
x' = -x3
x(0) = 0
x(t) = √(1/2t)
∫pi2(pi) -cos(x) dx
0
d/dx [ln(x)]
1/x
d/dt [cos(x(t))]
-sin(x(t)) * x'(t)
d/dt [ln(x(t))] = 3
x(t) = e3t + c
x' = 2
x(0) = 0
x(t) = 2t
∫01e-x^2 dx
-e-t^2 + 1
d/dx [xcos(x)]
cos(x) - xsin(x)