y = 4
e0 + e1
e + 1
sin(x)sec(x)
tan(x)
What are the dimensions of the following matrix?
3 4 6
8 2 1
2x3
Eliminate the parameter to write the rectangular equation represented by the following:
x = t
y = 4t
y = 4x
y = x2
concave up parabola
ln(0)
Does not exist
3(sin(x) + cos(x))2 - 6sin(x)cos(x)
3
3 2 + 3 -2
4 -2 2 -1
6 0
6 -3
Eliminate the parameter to write the rectangular equation represented by the following:
x = 4cos(t)
y = 2sin(t)
x2/16 + y2/4 = 1
y = |x| / x
y = 1 if x > 0
Solve.
ln(50) - ln(5) + ln(2) = ln(x)
20
tan(-x)cos(x)
-sin(x)
4 -1 * 2 -1
2 -3 0 6
8 -10
4 -20
Convert from polar coordinates to rectangular coordinates.
(-2, 7π/6)
((sqrt(3)), 1)
y = ex
y --> 0 as x --> -inf
y --> inf as x --> inf
contains the point (0, 1)
ln(x+5) = ln(x - 1) - ln(x - 1)
No solution
sin(x)tan(x) + cos(x)
sec(x)
Use your calculator to solve.
3x + 2y - 3z = 4
4x - 3y + 2z = 0
-3x + y - 4z = -5
x = 1
y = 2
z = 1
Convert the equation to rectangular coordinates.
r = 4sin(θ)
x2 + y2 - 4y = 0
y = ln(x)
y --> -inf as x --> 0-
y --> inf as x --> inf
contains the point (1, 0)
Solve.
2x2e2x + 2xe2x = 0
x = -1, 0
(1 - sin2(x)) / (csc2(x) - 1)
sin2(x)
The following message was encoded with a 2x2 matrix. The last four letters are POND.
1 4 -16 35 7 28 -12 51 3 100 -18 27 14 56 1 4 -7 115 -23 40 12 48 -14 109 6 68
A BIG FISH IN A SMALL POND
Convert the equation to polar coordinates and give an equation solved for r:
3x - y + 2 = 0
r = -2 / (3cos(θ) - sin(θ))