Solving Equations
Solving Absolute Value Equations
Solving Inequalities
Solving Absolute Value Inequalities
Surprise Bag
100

-5x=65

x=-13

100

∣5b∣=35

𝑏=7.    b=-7

100

−5x>−45

𝑥<9

100

∣x−10∣>11

x<9 or x>11

100

The two inequalities that are open

What is less than and what is greater than.

200

−48−x=−39

x=−9

200

∣5−b∣=12

                                           

                                   


    

b=17 and b=−7

200

−19+6x≤23

x≤7

200

The only times when we FLIP the inequality symbol

When we multiply or divide by a negative

300

4(2x−3)=12

x=3

300

13=∣−2x+5∣

−4=x.  and. 9=x

300

−1<x+8≤10

−9<x≤22

300

Spell your Algebra 1 teachers' last names.

Tesfom and Peláez

400

4(3x+4)+x+5=−5

x=−2

400

∣−c+12∣=14

c=−2 and c=26

400

2≥ x+9 or 11≤ 𝑥+9

x≤−7 or x≥2

500

3(−5x−3)=−10𝑥−(𝑥−6)

x=−3.75

500

12= -1∣3+3𝑥∣+15

x=0 and x=-2

500

−7≥−3x+8  AND  −3x+8>−19

 5≤x and x<9

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