Mole Conversions
Percent Composition
Empiricial forumula
Empirical Formula Difficult
FREE BALL
100

What is the mass of 2 moles of water (H₂O)?

36 grams

Explanation: Molar mass of H₂O = 18 g/mol; 2 moles × 18 g/mol = 36 g.)

100

What number must you multiply by after dividing the mass of an element by the mass of the compound to find percent composition?

100

100

This term describes the simplest whole-number ratio of atoms in a compound.

empirical formula

100

A compound is 36.86% nitrogen (N) and 63.14% oxygen (O). Its molar mass is 76 g/mol. Determine its empirical

Empirical formula: N₂O₃

  1. Assume 100 g: N = 36.86 g, O = 63.14 g.

  2. Convert to moles:

    • N: 36.8614.01≈2.63 mol14.0136.86≈2.63mol

    • O: 63.1416.00≈3.95 mol16.0063.14≈3.95mol

  3. Divide by smallest (2.63): N: 1, O: 1.5 → Multiply by 2: N₂O₃.

  4. Empirical mass: 2×14.01+3×16.00=76 g/mol2×14.01+3×16.00=76g/mol

100

Which NBA player became the first in league history to average a triple-double for an entire season, and in what year did he achieve this feat?  

Russell Westbrook 

2016-2017

200

How many moles are in 1.204×10241.204×1024 atoms of carbon?

2 moles
Explanation: Use Avogadro's number: 1.204×10246.022×1023=26.022×10231.204×1024=2 moles.

200

What is the percent composition of oxygen (O) in water (H₂O), given the molar mass of water is 18 g/mol and oxygen is 16 g/mol?

89% 

  • Molar mass of water (H₂O) = 18 g/mol

  • Molar mass of oxygen (O) = 16 g/mol

The formula for percent composition is:

Percent Composition=

(Mass of Element/Molar Mass of Compound)×100 

Percent Composition of O=(18g/mol)/(16g/mol)×100


200

A compound contains 48.0% carbon, 4.0% hydrogen, and 48.0% oxygen. This is its empirical formula.

 C₄H₄O₃

200

A compound contains 40.0% carbon (C), 6.7% hydrogen (H), and 53.3% oxygen (O). Its molar mass is 180 g/mol. Determine its empirical

CH₂O 

  1. Assume 100 g: C = 40.0 g, H = 6.7 g, O = 53.3 g.

  2. Convert to moles:

    • C: 40.012.01≈3.33 mol12.0140.0≈3.33mol

    • H: 6.71.008≈6.65 mol1.0086.7≈6.65mol

    • O: 53.316.00≈3.33 mol16.0053.3≈3.33mol

  3. Divide by smallest (3.33): C: 1, H: 2, O: 1 → CH₂O.

  4. Empirical mass: 12.01+2×1.008+16.00=30.03 g/mol12.01+2×1.008+16.00=30.03g/mol.

200

In 2022, this player became the all-time leading goal scorer in international soccer history, surpassing Ali Daei’s record of 109 goals.

Cristiano Ronaldo

300

How many atoms are in 12 grams of carbon (C)?

6.022×10236.022×1023 atoms
Explanation: Molar mass of carbon = 12 g/mol; 12 g = 1 mole; 1 mole = 6.022×10236.022×1023 atoms.

300

Calculate the percent composition of sulfur (S) in sulfuric acid (H₂SO₄), given the molar masses: H = 1 g/mol, S = 32 g/mol, O = 16 g/mol.

32.65%

300

The empirical formula of a compound with 36.0% carbon, 4.0% hydrogen, 28.0% nitrogen, and 32.0% oxygen.

C₃H₄N₂O₂

300

A compound is 26.56% potassium (K), 38.03% oxygen (O), and the remainder chromium (Cr). Determine its empirical formula.

K₂Cr₂O₇ 

  1. Assume 100 g: K = 26.56 g, O = 38.03 g, Cr = 100 - 26.56 - 38.03 = 35.41 g.

  2. Convert to moles:

    • K: 26.5639.10≈0.68 mol39.1026.56≈0.68mol

    • O: 38.0316.00≈2.38 mol16.0038.03≈2.38mol

    • Cr: 35.4152.00≈0.68 mol52.0035.41≈0.68mol

  3. Divide by smallest (0.68): K: 1, O: 3.5, Cr: 1 → Multiply by 2: K₂Cr₂O₇.

300

This NFL team holds the record for the most Super Bowl appearances

New England Patriots

400

At STP, how many atoms are in 11.2 liters of neon gas (Ne)?

3.011×10233.011×1023 atoms
Explanation: At STP, 11.2 liters = 0.5 moles; 0.5 moles × 6.022×10236.022×1023 atoms/mol = 3.011×10233.011×1023 atoms.

400

What is the percent composition of water in magnesium sulfate heptahydrate (MgSO₄·7H₂O), and water is 126 g/mol?

51.22%

The molar mass of magnesium sulfate heptahydrate (MgSO₄·7H₂O) is calculated by summing the atomic masses of its constituent elements:

  1. Magnesium (Mg): 24.305 g/mol

  2. Sulfur (S): 32.07 g/mol

  3. Oxygen (O): 16.00 g/mol (multiplied by 11, as there are 4 in MgSO₄ and 7 in 7H₂O)

  4. Hydrogen (H): 1.008 g/mol (multiplied by 14, as there are 14 in 7H₂O)


Molar Mass of (MgSO₄·7H₂O)=24.305+32.07+(11×16.00)+(14×1.008)
=24.305+32.07+176.00+14.112=246.487 g/mol=24.305+32.07+176.00+14.112=246.487g/mol


 

400

A compound with 11.25% carbon and 88.75% chlorine has this empirical formula. Its molecular formula mass is 320 g/mol.

C₃Cl₈

400

A compound is 49.48% carbon (C), 5.19% hydrogen (H), 16.48% oxygen (O), and 28.85% nitrogen (N). Its molar mass is 194 g/mol. Determine its empirical

C₄H₅N₂O

  1. Assume 100 g: C = 49.48 g, H = 5.19 g, O = 16.48 g, N = 28.85 g.

  2. Convert to moles:

    • C: 49.4812.01≈4.12 mol12.0149.48≈4.12mol

    • H: 5.191.008≈5.15 mol1.0085.19≈5.15mol

    • O: 16.4816.00≈1.03 mol16.0016.48≈1.03mol

    • N: 28.8514.01≈2.06 mol14.0128.85≈2.06mol

  3. Divide by smallest (1.03): C: 4, H: 5, O: 1, N: 2 → C₄H₅N₂O.

  4. Empirical mass: 4×12.01+5×1.008+2×14.01+16.00=97.10 g/mol4×12.01+5×1.008+2×14.01+16.00=97.10g/mol.

 

400

This player holds the record for the most NBA All-Star Game MVP awards, with four total wins.

Kobe Bryant

500

What is the mass of 1.806×10241.806×1024 molecules of carbon dioxide (CO₂)?

132 grams
Explanation:

  1. Convert molecules to moles: 1.806×10246.022×1023=36.022×10231.806×1024=3 moles.

  2. Molar mass of CO₂ = 44 g/mol; 3 moles × 44 g/mol = 132 g.

500

What is the percent composition of iron (Fe) in potassium ferricyanide (K₃[Fe(CN)₆])?

16.96%

  1. Molar masses of elements:

    • Iron (Fe): 55.85 g/mol

    • Potassium (K): 39.10 g/mol

    • Carbon (C): 12.01 g/mol

    • Nitrogen (N): 14.01 g/mol


    • Molar mass of K₃[Fe(CN)₆]:

      • Potassium (K): 3 × 39.10 = 117.3 g/mol

      • Iron (Fe): 1 × 55.85 = 55.85 g/mol

      • Carbon (C): 6 × 12.01 = 72.06 g/mol

      • Nitrogen (N): 6 × 14.01 = 84.06 g/mol
        Total molar mass = 117.3 + 55.85 + 72.06 + 84.06 = 329.27 g/mol  Total molar mass = 117.3 + 55.85 + 72.06 + 84.06 = 329.27 g/mol



        • Percent composition of iron (Fe):
          55.85329.27×100≈16.96%329.2755.85×100≈16.96%





500

Caffeine has 49.48% carbon, 5.19% hydrogen, 16.48% oxygen, and 28.85% nitrogen. Its empirical? (molar mass = 194.19 g/mol).

C₄H₅N₂O

500

A compound is 11.25% carbon (C) and 88.75% chlorine (Cl). Its molar mass is 320 g/mol. Determine its empirical

C₃Cl₈ 

  1. Assume 100 g: C = 11.25 g, Cl = 88.75 g.

  2. Convert to moles:

    • C: 11.2512.01≈0.937 mol12.0111.25≈0.937mol

    • Cl: 88.7535.45≈2.503 mol35.4588.75≈2.503mol

  3. Divide by smallest (0.937): C: 1, Cl: 2.67 → Multiply by 3: C₃Cl₈.

500

when did fortnite come out

2017

M
e
n
u