probability distribution
expectation
variance
binomial distribution
100

Two tetrahedral dice, each with faces labelled 1, 2, 3 and 4, are thrown and the random variable X represents the sum of the numbers shown on the dice.

(i) Illustrate the distribution and describe the shape of the distribution.


It is a symetrical distribution

100

State the formula for expectation

E(X) = Σxp

100

State the formula for variance. 


Var(X) = Σx2p - [E(X)]2

100

What is the formula of binomial distribution?

P(X) = (nCx)(px)(qn-x)

200

Two tetrahedral dice, each with faces labelled 1, 2, 3 and 4, are thrown and the random variable X represents the sum of the numbers shown on the dice.

(i) Find the probability distribution of X.

Two tetrahedral dice, each with faces labelled 1, 2, 3 and 4, are thrown and the random variable X represents the sum of the numbers shown on the dice.

(i) Find the probability distribution of X.

200

No. of people   Probability

         1                0.35

         2                0.375

         3                0.205

         4                0.065

         5                0.005

        >5                0

Find the expected value

E(X) = 2

200

No. of people   Probability

         1                0.35

         2                0.375

         3                0.205

         4                0.065

         5                0.005

        >5                0

Find the variance value

Var(X) = 0.86
200

How to know if a distribution is binomial 

A binomial distribution counts the number of successes in a fixed number of trials

300

The random variable X is given by the sum of the scores when two ordinary dice are thrown.

(i) Find the probability distribution of X.

2 = 1/36

3 = 2/36

4 = 3/36

5 = 4/36

6 = 5/36

7 = 6/36

8 = 5/36

9 = 4/36

10 = 3/36

11 = 2/36

12 = 1/36

300

r          Pr

0        0.2

1        0.3

2        0.4

3        0.1

(i) Find the E(X2)

E(X2) = 2.8

300

r          Pr

0        0.2

1        0.3

2        0.4

3        0.1

(i) Find the Var(X)

Var(X) = 0.84

300

Extensive research has shown that 1 person out of every 4 is allergic to a particular grass seed. A group of 20 university students volunteer to try out a new treatment. 

(ii) What is the probability that exactly 2 people are allergic

P(X=2) = 0.067

400

The random variable X is given by the sum of the scores when two ordinary dice are thrown.

(i) Find P(X>8).

(ii) Find P(X=even)

(i) 5/18

(ii) 1/2

400

x       P(X=x)

-3         0.15

-1         0.3

0          0.15

4          0.4

find the expected value

E(X) = 0.85

400

x       P(X=x)

-3         0.15

-1         0.3

0          0.15

4          0.4

find the variance value

Var(X) = 7.3275

400

George wants to invest some of his monthly salary. He invests a certain amount of this every month for 18 months. For each month there is a probability of 0.25 that he will buy shares in a large company, a probability of 0.15 that he will buy shares in a small company and a probability of 0.6 that he will invest in a savings account.

(ii) Find the probability that George will buy shares in a small company in at least 3 of these 18 months.

(ii) 0.520

500

The probability distribution of a random variable X is given by 

P(X=r) = kr for r = 1,2,3,4

(i) Find the value of constant k 

(i) k=0.1

500

x       P(X=x)

-3         a

-1         b

0          0.15

4          0.4

Given that E(X) = 0.75. Find the values of a and b

a = 0.2

b = 0.25

500

x      P(X=x)

2       5/16

3        1/16

4        3/8

5        1/8

6        1/16

7        1/16

Find the variance value

Var(X) = 2.1875

500

A box contains 300 discs of different colours. There are 100 pink discs, 100 blue discs and 100 orange discs. The discs of each colour are numbered from 0 to 99. Five discs are selected at random, one at a time, with replacement. Find:

(i) the probability that no orange discs are selected

(i) 0.132

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