Simplify:
3^4 x 3^2
Ans
3^6
Evaluate:
log(1000)
Ans:
3
Solve:
2^x = 8
Ans:
x = 3
Solve:
log base 2 (x) = 5
Ans:
x = 32
A bacteria pop doubles every hr. if there are 200 bacteria now, how many in 3 hrs?
200(2^3) = 1600
Rewrite with a positive exponent:
x^-3
Ans:
1/x^3
Expand:
log(5x)
Ans:
log(5) + log(x)
Solve:
5^(x+1) = 25
Ans:
x = 1
solve:
log(x) + log(2) = 3
Ans:
x = 500
rewrite in exp form:
log base 5 (125) = 3
Ans:
5^3 = 125
Simplify:
(5^3)^2
Ans:
5^6
Condense:
log(x) + 2log(y)
Ans:
log(xy^2)
Solve:
7^x = 4
Ans:
x = log4 / log7
Solve:
log base 5 (2x - 1) = 2
Ans:
x = 13
Solve for time:
A = 500e^(0.12t)
Find t when A = 800
Ans:
800 = 500e^(0.12)
t = log(1.6)/0.12
Simplify:
(2^7) / (2^3)
Ans:
2^4 = 16
Rewrite using change of base:
log base 3 x (10)
Ans:
log(10) / log(3)
Solve:
3^2x = 27
Ans:
x = 3/2
Solve:
log(x) - log(x-3) = 1
Ans:
x = 10/3
T(t) = 22 + (68)e^(-1.5t)
Find Temp at t = 10
Ans:
22 + 68e^(-1.5)
Write as a single Power:
4^3 x 8^2
Ans:
(2^2)^3 (2^3)^2
= 2^(6 + 6)
= 2^12
Simplify:
log [(a^3)/(b^1/2)]
3log(a) - 1/2 log(b)
Solve:
4^x+1 = 10
Ans:
x = log base 4 (10) - 1
log(x+4) = 2
Ans:
e^2 - 4
Radioactive decay:
A substance has a half life of 12 years. Write an equation for the amount remaining from an initial 80 grams.
Ans:
A(t) = 80 (1/2)^(t/12)