Complex numbers
(3-4i)+(-5+7i)
-2+3i
How many imaginary solutions does x2 + 6x + 9 =0 have?
none
x3 * x5
x8
Define the imaginary number (i).
sqrt(-1)
(3-4i)-(-5+7i)
8-11i
Solve (x-3)2=-9
3+3i and 3-3i
x3/x5
1/x2
Write a^{1.5} in radical form
sqrt (a3)
(3-4i)(-5+7i)
13+41i
cube root of (x-3)+4=2
-5
x5/x-3
x8
Simplify t^{-2/7} as a fraction with a radical.
1/seventh root of t2
(3-4i)(3+4i)
25
square root (x-3)+4=2
no solution
(a2b3c5)-2
1/(a4b6c10)
Evaluate 16^{1/4} times 64^{1/2} no calculators!
16
(3-4i)2
-7-24i
3x2-2x-3=0
(1+root10)/3 and (1-root10)/3
Write without exponents x3/4
fourth root of x3
Solve (4x + 3)^{0.25} = 1
-1/2