Addition/Subtraction
Multiplication/Rounding
Unit Conversion
Area & Perimeter
Mystery
100
1,006 + 983 = ?
1,989
100
Round 5,790 to the nearest thousand
~6,000
100
8,135 kg is 8 ___ 135 g
8 kg 135 g
100
What are the formulas for area and perimeter?
A = L x W
P = L + W + L + W
100
30m 67cm = _________ cm
3,067 cm
200
2,091 - 1,394 = ?
697
200
700 x 10 = ?
7,000
200
342, 645 mL = ____ L _____ mL
342 L 645 mL
200
L = 6 cm
W = 5 cm
Find the area
A = L x W
A = 6 x 5
A = 30 square cm
200
242,561 - 49,702 = ?
192,859
300
5,311 - 2,199 = ?
3,112
300
480,500 + 340,579 = ?
Then, round your answer to the nearest hundred thousand.
821,079
~800,000
300
Put the following numbers in order:
33kg100g
31,900g
32,350g
30kg500g
30kg500g
31,900g
32,350g
33kg100g
300
A rectangle is 9cm long and 4cm wide. What is the area and perimeter of the rectangle?
A = 9 x 4 = 36 square cm
P = 9 + 4 + 9 +4 = 26 cm
300
Azarah traveled from Chicago to Australia, the distance was 9,818 miles. Markyila traveled from Chicago to Japan, the distance was 6,309 miles. How many more miles did Azarah travel than Markyila?
Show your work!9,818 - 6,309 = 3,509 miles
400
479108170 + 324249 = ?
479,432,419
400
371 thousands + 9 ten thousands
Then, round to the nearest thousand.
461,000
~460,000
400
Sarah bought a 5kg bag of cherries at the market and ate 175g of them on the way home. How many grams of cherries did Sarah have left by the time she got home?
5kg = 5,000g
5,000g - 175g = 4,825g
Sarah had 4,825g of cherries left by the time she got home.
400
77 m
P = 260
Find the width.
77 + 77 = 154
260 - 154 = 106
106 split into 2 is 53.
W = 53 m
400
A playground is 58m wide and 90m long. What is its perimeter?
P = 90 + 58 + 90 + 58 = 296m
500
600,000 - 592,569 = ?
7,431
500
100,000 x 60 = ?
6,000,000
500
A bottle holds 1 L of lemonade. Rachel fills 5 glasses with lemonade. She puts 150 mL in each glass. How much lemonade is left in the bottle?
150 x 5 = 750mL
1L = 1,000mL
1,000 - 750 = 250mL
250mL of lemonade is left in the bottle.500
A postcard has an area of 28 square inches and a perimeter of 22 inches. What are the length and width of the postcard?
L = 7
W = 4
500
The perimeter of the classroom is 354m. The perimeter of the gym is 6 times as much as the perimeter of the classroom. If the width of the classroom is 83 m. What is the perimeter and the length of the gym?
83 x 2 = 166
354 - 166 = 188
188 divided by 2 = 94 - length of the classroom
354 x 6 = 2,124 - Perimeter of the gym
94 x 6 = 564
The length of the gym is 564m!