1-guruh
2-guruh
3- guruh
4-guruh
100

Rejalashtiririlgan masalalar soni har bir kunga quyidagicha o'zgarib boradi:

1-kun    2-kun   3-kun    4-kun    ............

5 ta        10 ta     15 ta      20 ta  ............

natijada quyidagi ketma ketlik hosil boldi

         5,10,15,20,25........

savol bu qnday progressiya,ayirma nechaga teng?

Bu arifmetik progressiya.ayirmasi ya'ni d=5 ga

100

3,6,12,24,48,.......  bu qanday progressiya,mahrajini toping?

Bu geometrik progressiya

q=6/3=2  maxraji 2 ga teng

100

25,21,17,.......arifmetik progressiyaning birinchi hadi va ayirmasini ayting.

Birinchi hadi 25 ga teng.

ayirmasi ya'ni d=17-25 -4    -4 ga teng

100

8,16,24....... geometrik progressiyaning birinchi hadi va mahrajini toping?

Birinchi hadi 8 ga teng.

q=b1:b2=16:8=2    2 ga teng

200

Arifmetik progressiyada ayirmani topish formulasini ayting?

d=a2-a1

200

Hisoblang:  2*2*2*2*2*2*2*2*2*2

2 ning 10 darajasi ya'ni  1024 ga teng

200

geometrik progressiyada maxraj qanday topiladi?

q=b2:b1

200

Hisoblang:3*3*3*3*-31+5*5*5

175

300

Hisoblang:a1=2 ,d=3 bo'lsa,  a15 ni toping?

a15=a1+ 14d

a15=2+14*3

a15=2+28

a15=30

300

Hisoblang:agar a1=3,  d=4 bo'lsa, a20 ni toping?

a20=a1+ 19d

a20=3+19*4

a20=3+76

a20=79

300

Hisoblang:a1=7, a16=67 bo'lsa,uning ayirmasini toping?

d=a16-a1

15d=67-7

15d=60

d=4

300

Hisoblang: a1=-4, a9=0 bo'lsa ,uning ayirmasini toping?

d=a9-a1

8d=0-(-4)

8d=4

d=2

400

Agar geometrik progressiyada: b1=12, q=2 bo'lsa ,dastlapki 5 ha hadini ayting

12,24,48,96,192

400

Agar geometrik progressiyada: b1=-3, q=-4 bo'lsa ,uning dastlapki 4 ta hadini ayting.bu qanday progressiya turiga kiradi?

-3,12,-48,192

400

Geometrik progressiya : b1=3, q=10 bo'lsa,b4 ni hisoblang

b4=b1*q^3

b4=3*10^3

b4=3*1000

b4=3000

400

Sizlar bonusga ega bo'ldingiz!!!!!

sizlarga 400 ball sovg'a!!!

500

Geometrik progressiyada 

6,12,24,.........,192

                       ---- tagiga chizilgan hadning nomerini toping

b1=6,  b2=12,    bn=192

q=b2:b1=12:6=2  q=2

192=6*2^n-1

192/6=2^n-1

32=2^n-1

2^5=2^n-1

5=n-1

n=6

500

Cheksiz kamayuvchi geometrik progresiyani yig'indisini topih formulasini ayting(yozib ko'rsating)

S=b1/1q

500

geometrik progresiyani dastlapki n ta hadini yig'indisii topish formulasini aytin(yozib ko'rsating)

Sn=b1(1-q^n)/1-q

500

Arifmetik progressiyani dastlapki n ta hadini yig'indisini topish formulasini ayting(yozib ko'rsating)

Sn=a1+an/2  *n

M
e
n
u