7.1 Ratios and Rates
7.2 Complex Rates
7.3 Proportions
7.4 Scale Models
7.5 Proportional Relationships
100

Write each ratio in lowest terms.

8 to 12

2 to 3

100

3/4/2 x 4/[] = 3/8

4

100

Solve for each proportion.(100-500)

10/15=8/x


x=12

100

Find the missing scale factor or length.(100-500)

toy car   1 in:64 in.  AL 188.3 in.



AL=Actual Length   ML= Model Length


2.94 in.

100

Use the constant of proportionality to find the missing terms.(100-200)

[x/y]  0.5/1.5, []/7.5, 4/[]

2.5;12

200

(51/1), (  /2), (   /3), (330/  )

110;165;6

200

Express each number as a fraction in lowest terms.[keep it in a improper fraction]

(200-300)

27


27/1

200

16/24=v/15

v=10

200

House

0.25 in. : 1ft   AL=60 ft

15 in.

200

[x/y]  4/3/4, []/6, 1.6/[]

2;4.8

300

Determine whether each comparison can be written as a rate. If so, write the simplified rate & unit rate.If not, write not a rate. ( For 300 & 500 )

34 mi in 4 hr

17 mi :2 hr;8.5 mi/hr

300

1.55

31/20

300

w/21=24/14

w=36

300

Room

ML=3/4 in.  AL=12ft

1 in. : 60ft

300

find the constant of proportionality and write the equation describing the proportional relationships.(300-400)

[x/y]  0.75/3, 1.5/6

k=4;y=1.25x

400

A grade of 85 compared to a grade of 92.

not a rate.

400

Complete each ratio table.

4/1, []/2.5, 30/[]

10, 7.5

400

3:5=1.2:o

o=2

400

Coal car

ML-8in.  AL=64ft

1in. : 8ft

400

[x/y]  4/5, 6/7.5

k=1.25;y=1.25x

500

5´4in. compared to 4 ft 10in.

not a rate.

500

Solve.

20/70=4/n

n=14

500

z is to 9/10 as 2 is to 4& 1/2

z=2/5

500

House

0.25in. : 1ft  ML=18.75in.

AL=75ft

500

ARE YOU READY FOR THE TEST?

YES  OR  NO

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