Work
Kinetic Energy & Velocity
GPE & Height
Total Mechanical Energy
Ms. Cory
100

Someone pushes a textbook across a desk. They push it 0.4 m and use a force of 5.2 N. How much work did they do on the book?

W = F * d
W = 5.2 * 0.4
W = 2.16 J

100

A 1200 kg car is traveling at 17 m/s. What is the car's kinetic energy?

KE = 1/2 * m * v2 
KE = 1/2 * 1200 * 17
KE = 173,400 J

100

Calculate the GPE of a pencil resting on a table, if the pencil has a mass of 0.03 kg and the table's height is 0.7 m

GPE = m * g * h
GPE = 0.03 * 9.8 * 0.7
GPE = 0.2058 J

100

A falling apple has a GPE of 7.5 J and a KE of 2.4 J. What is its TME?

7.5 + 2.4

9.9 J

100

What is Ms. Cory's first name? 

To get this right, you must have the correct spelling!

Eleanor

200

An athlete lifts a weight 0.8 m into the air. The weight has a mass of 100 kg. How much work did the athlete do on the weight? 

Fg = m * g
Fg = 100 * 9.8
Fg = 980 N

W = F * d
W = 980 * 0.8
W = 784 J

200

A canoe has 170 J of kinetic energy, until someone pushes on it. The push causes the boat to speed up, and now it has 250 J of kinetic energy. How much work did the person do on the boat? 

W = KEf - KEi

W = 250 - 170

W = 80 J

200

A coconut falls out of a tree. It starts at a height of 11 m and ends up on the ground. The coconut has a mass of 2.1 kg. 

What is the GPE of the coconut once it's on the ground?

0 J 


(its height is 0)
200

A sled is in a closed system. Its TME at the top of a hill is 1800 J. What will be its TME at the bottom of the hill? How do you know?

1800 J

It is unchanged because the sled is in a closed system (meaning TME cannot change). 

200

Where did Ms. Cory study abroad in college? 

Korea (Seoul)

300

A student is flying a kite. The kite has a mass of 0.07 kg. She pulls on the kits, causing the kite to speed up from 0.9 m/s to 1.6 m/s. How much work did she do on the kite?

W = 1/2 * m * vf2 - 1/2 * m * vi2 

W = 1/2 * 0.07 * 1.62 - 1/2 * 0.07 * 0.92

W = 0.06125 J

300

The moon has a mass of 7.35 * 1022 kg. It is moving at a velocity of about 3.683 * 106 m/s. What is the kinetic energy of the moon?

KE = 1/2 * m * v2 
KE = 1/2 * 7.35 E 22 * (3.683 E 6)
KE = 4.98 E 35
KE = 4.98 * 1035 J

300

A dolphin jumps into the air. At its peak, it has 1225 J of GPE. If the dolphin's mass is 50 kg, what height did the dolphin jump to?

GPE = m * g * h
1225 = 50 * 9.8 * h
1225 = 490 * h
2.5 m = h

300

A ball is rolling down a hill in a closed system. At the top of the hill, its TME is 42 J. As it rolls, friction and air resistance do -18 J of work on the ball. 

What will be the ball's TME at the bottom of the hill?

TMEi + Wext = TMEf

42 + -18 = TMEf

24 J = TMEf

300

How old is Ms. Cory? 

Whichever group gets the closest gets the point. 

31

400

A pencil is rolling across a desk in an open system. The pencil starts with 7.1 J of TME, and ends with 0 J of TME. How much work did friction and air resistance do on the pencil? 

Wext = TMEf - TMEi
Wext = 0 - 7.1
Wext = -7.1 J

400

What is the velocity of a tennis ball that has a kinetic energy of 42 J and a mass of 0.8 kg?

KE = 1/2 * m * v2
42 = 1/2 * 0.8 * v
42 = 0.4 * v 
105 = v
10.25 m/s = v

400

A soccer player kicks a soccer ball into the air in a closed system. The ball starts on the ground, where it has 68 J of kinetic energy from the kick. 

When the ball reaches its peak in the air, its kinetic energy is 0. What is the ball's GPE at this peak? 

TME = GPE + KE
TMEi = 0 + 68
TMEi = 68 J

IN a closed system, TME= TMEf so:
TMEf = 68 J

TME = GPE + KE
68 = GPE + 0
68 J = GPE

400

What is the TME of a 6.8 kg bird that is flying at a velocity of 3.1 m/s at a height of 30 m?

KE = 1/2 * m * v2
KE = 1/2 * 6.8 * 3.12
KE = 32.674

GPE = m * g * h
GPE = 6.8 * 9.8 * 30
GPE = 1911

TME = GPE + KE
TME = 1911 + 32.674
TME = 1943.674 J

400

When did Ms. Cory get married? (say the month and year)

July 2025

500

A ball is falling. When it starts, it has 45 J of TME. When it hits the ground, it is traveling at a velocity of 4 m/s. The ball has a mass of 2.5 kg. 

How much work did air resistance do on the ball while it was falling? 

GPEf = 0 J (on the ground)

KEf = 1/2 * 2.5 * 42
KEf = 20 J

TMEf = GPEf + KEf
TMEf = 0 + 20
TMEf = 20 J

TMEi + Wext = TMEf 
 45  + Wext = 20
       Wext = -25 J

500

A 75 kg skater is in a closed system. She starts at the top of a ramp (h=9 m) from rest. What will be her total mechanical energy at the bottom of the ramp?

TMEi = GPEi + KEi   

GPEi = m * g * h
GPEi = 75 * 9.8 * 9
GPEi = 6615 J

KEi = 0 (skater starts from rest)

TMEi = 6615 + 0
TMEi = 6615

In a closed system, TMEi = TMEf

TMEf = 6615 J

500

What did Ms. Cory major in in college?

Chemistry

M
e
n
u