Solve for L
A = LWH
L = A/WH
3y + 11 = -16
y = -9
Solve
|x| = 3
x = 3, x = -3
|-2x+6| = 6
0, 6
What is the first step when solving this problem:
|x-5| + 3 = 10
Subtract 3 from both sides (clean up the outside and isolate the absolute value)
Solve for m:
m - t = p
m = p + t
6 = 1 - b
b = -5
|x| = -4
NO SOLUTION
Absolute value will never evaluate to be a negative number.
|5x| + 5 = 45
8, -8
P = 4S is the formula for the perimeter of a square. Is this an example of a literal equation also? Why?
Yes, literal equations have more than one variable and formulas are examples of literal equations.
Solve for x:
xy = z
x = z/y
n + 5n + 7 = 43
n = 6
|x+4| = 8
4, -12
3 |−8x| + 8 = 80
-3, 3
Why can't |2x-9| = -5 be true?
Absolute value equations cannot be set equal to a negative number. Abs. val. is the distance from zero and distance cannot be negative.
Solve for y:
y - b = mx
y = mx + b
-4(2z + 6) - 12 = 4
z = -5
|−3r| = 9
3, -3
3 |3 − 5r| − 3 = 18
-4/5, 2
What kind of answer will you get to a literal equation?
The answer will be an expression.
Solve for w:
5w + 12c = 9
3/2(x-2)-5=19
x = 18
|x/5| = 2
10, -10
6 |1 − 5x| − 9 = 57
-2, 12/5
Is -5 a solution to |-2x-1| = 11?
No.